Unique Rank value for a subgroup within a group

Question

I am trying to get a unique rank value (e.g. {1, 2, 3, 4} from a subgroup in my data. SUMPRODUCT will produce ties{1, 1, 3, 4}, I am trying to add the COUNTIFS to the end to adjust the duplicate rank away.

                subgroup
col B   col M    rank
LMN       01      1
XYZ       02        
XYZ       02    
ABC       03    
ABC       01    
XYZ       01    
LMN       02      3
ABC       01    
LMN       03      4
LMN       03      4  'should be 5
ABC       02    
XYZ       02    
LMN       01      1  'should be 2   

So far, I've come up with this.

=SUMPRODUCT(($B$2:$B$38705=B2)*(M2>$M$2:$M$38705))+countifs(B2:B38705=B2,M2:M38705=M2)

What have I done wrong here?

Answer 1

Solution basing on OP

Studying your post demanding to post any alternatives, I got interested in a solution based on your original approach via the SUMPRODUCT function. IMO this could show the right way for the sake of the art:

Applied method

Get

• a) all current ids with a group value lower or equal to the current value

  MINUS

• b) the number of current ids with the identical group value starting count from the current row

  PLUS

• c) the increment of 1

Formula example, e.g. in cell N5:

=SUMPRODUCT(($B$2:$B$38705=$B5)*($M$2:$M$38705<=$M5))-COUNTIFS($B5:$B$38705,$B5,$M5:$M$38705,$M5)+1

P.S.

Of course, I agree with you preferring the above posted solution, too :+)

Answer 2

The good news is that you can throw away the SUMPRODUCT function and replace it with a pair of COUNTIFS functions. The COUNTIFS can use full column references without detriment and is vastly more efficient than the SUMPRODUCT even with the SUMPRODUCT cell ranges limited to the extents of the data.

In N2 as a standard function,

=COUNTIFS(B:B, B2,M:M, "<"&M2)+COUNTIFS(B$2:B2, B2, M$2:M2, M2)

Fill down as necessary.

      

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