CODEWITHSUNDEEP
bashawk
user3891747
user3891747

Reputation: 89

Separate columns in one line using Bash script

I am using bash scripting in Linux. I have a variable that looks like this:

a="1-1-1 1-1-2 1-1-3 1-1-4"

I want to separate columns with values equal to or greater than 1-1-3 using AWK.

My output should be:

1-1-3 1-1-4

Can someone help me with this?

Upvotes: 1

Views: 105

Answers (3)

glenn jackman
glenn jackman

Reputation: 246807

sort's -V option gives you "version" sorting that might be helpful:

$ a="2-0-0 1-1-1 1-1-2 1-1-3 1-1-4"
$ tr ' ' '\n' <<<"$a" | sort -V
1-1-1
1-1-2
1-1-3
1-1-4
2-0-0

Upvotes: 1

Casimir et Hippolyte
Casimir et Hippolyte

Reputation: 89557

You can do it without a loop, if you use the space as record separator:

echo $a | awk -v RS=' ' -v ORS=' ' '{$1=$1} $1>="1-1-3"'

Upvotes: 1

P.P
P.P

Reputation: 121387

You can loop over the line and compare:

echo $a | awk -v ORS=' ' '{for(i=1;i<=NF;i++) if($i >= "1-1-3") print $i;}'

Upvotes: 1

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