Reputation: 1271
Is there a one-line method to obtain character length for strings held within a specific column of a tab-delimited .txt file and then append these counts onto the final column (number of columns may be variable)?
Sample Data:
1 AA
2 BBB
3 CCCCC
4 EE
5 DDD
6 AAA
7 FFFFF
8 AA
9 BBB
10 NNN
To get the counts, I have attempted to use:
perl -lane 'print length $F[2]' in > out
perl -F, -Mopen=:locale -lane 'print length $F[2]' in > out
However, the results are empty.
I have also tried:
perl -lane '$_.=$F[2]; print length $_'
But this, as I now realise, prints the number of characters for the entire line rather than a specific column.
I am not sure how I would then append the final column.
Desired Output (when counting column 2):
1 AA 2
2 BBB 3
3 CCCCC 5
4 EE 2
5 DDD 3
6 AAA 3
7 FFFFF 5
8 AA 2
9 BBB 3
10 NNN 3
Upvotes: 1
Views: 102
Reputation: 126722
It seems that you were close. Perl array indices start at zero, so how about using the length of $F[1]
? You will also need some sort of separator
perl -lape '$_ .= "\t". length($F[1])' input
1 AA 2
2 BBB 3
3 CCCCC 5
4 EE 2
5 DDD 3
6 AAA 3
7 FFFFF 5
8 AA 2
9 BBB 3
10 NNN 3
If you want the output exactly as you show, then you will need to use printf
like this
perl -lane 'printf qq{%-4d%-8s%d\n}, @F, length($F[1])' input
1 AA 2
2 BBB 3
3 CCCCC 5
4 EE 2
5 DDD 3
6 AAA 3
7 FFFFF 5
8 AA 2
9 BBB 3
10 NNN 3
Upvotes: 3