CODEWITHSUNDEEP
java
saathu
saathu

Reputation: 59

avoid using multiple split method

I have a string like this.

   //Locaton;RowIndex;maxRows=New York, NY_10007;1;4

From this i need to get the contry name New York only. How it can possible in a single step code.

i used..

   String str = "Locaton;RowIndex;maxRows=New York, NY_10007;1;4 ";
   str = str.split("=")[1];
   str = str.split(",")[0]

the above code contails lots of splits.How can i avoid thiis. i want to get the contry name only using single code.

Upvotes: 1

Views: 87

Answers (2)

M Sach
M Sach

Reputation: 34424

Use capture groups with regex which perfect capturing the specific data from string. 

  String str = "Locaton;RowIndex;maxRows=New York, NY_10007;1;4 ";
   String pattern = "(.*?=)(.*?)(,.*)";
   Pattern r = Pattern.compile(pattern);

   Matcher m = r.matcher(str);

   if (m.find()) {
       System.out.println("Group 1: " + m.group(1));
       System.out.println("Group 2: " + m.group(2));
       System.out.println("Group 3: " + m.group(3));
   }

Here is the output 

Group 1: Locaton;RowIndex;maxRows=
Group 2: New York
Group 3: , NY_10007;1;4

Upvotes: 1

Abdelhak
Abdelhak

Reputation: 8387

Try to use this regular expression "=(.*?)," like this:

   String str = "Locaton;RowIndex;maxRows=New York, NY_10007;1;4 ";
    Pattern pattern = Pattern.compile("=(.*?),");
    Matcher matcher = pattern.matcher(str);
    if (matcher.find()) {
        System.out.println(matcher.group(1));
    }

Output:

   New York

Using matcher.group(1) means capturing groups make it easy to extract part of the regex match,parentheses also create a numbered capturing group. It stores the part of the string matched by the part of the regular expression inside the parentheses.

 Match "Locaton;RowIndex;maxRows=New York, NY_10007;1;4 "
 Group 1: "New York"

Upvotes: 4

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