pjehyun
pjehyun

Reputation: 931

find a minimum value in an array of floats

How would one go about finding the minimum value in an array of 100 floats in python? I have tried minindex=darr.argmin() and print darr[minindex] with import numpy (darr is the name of the array)

but I get: minindex=darr.argmin()

AttributeError: 'list' object has no attribute 'argmin'

what might be the problem? Is there a better alternative?

Upvotes: 35

Views: 324804

Answers (4)

ArtEm
ArtEm

Reputation: 947

If min value in array, you can try like:

>>> mydict = {"a": -1.5, "b": -1000.44, "c": -3}
>>> min(mydict.values())
-1000.44

Upvotes: 0

Pedro Machado
Pedro Machado

Reputation: 156

You need to iterate the 2d array in order to get the min value of each row, then you have to push any gotten min value to another array and finally you need to get the min value of the array where each min row value was pushed

def get_min_value(self, table):
    min_values = []
    for i in range(0, len(table)):
        min_value = min(table[i])
        min_values.append(min_value)

    return min(min_values)

Upvotes: 0

unutbu
unutbu

Reputation: 880299

If you want to use numpy, you must define darr to be a numpy array, not a list:

import numpy as np
darr = np.array([1, 3.14159, 1e100, -2.71828])
print(darr.min())

darr.argmin() will give you the index corresponding to the minimum.

The reason you were getting an error is because argmin is a method understood by numpy arrays, but not by Python lists.

Upvotes: 25

Greg Hewgill
Greg Hewgill

Reputation: 993931

Python has a min() built-in function:

>>> darr = [1, 3.14159, 1e100, -2.71828]
>>> min(darr)
-2.71828

Upvotes: 86

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