CODEWITHSUNDEEP
laravellaravel-5
Graham T
Graham T

Reputation: 966

Checking Stripe subscription status in 5.2

How is everyone checking their users subscription status in 5.2?

In 5.1 it was easy $user->subscribed(), but now you have to specify a plan name as an argument $user->subscribed('plan-name').

To grab the user's plan name, I created a Subscription model to go along with the subscription table that is created by Cashier. Then created an association between User and Subscription, so I can get a user's plan name like $user->subscription['name'], then I just inserted that into the subscribed call:

$user->subscribed( $user->subscription['name'] )

It looks fine to me, and outputs the plan name in Tinker correctly, but ends up breaking things and throwing this error on some of my routes:

Call to undefined method Illuminate\Database\Query\Builder::active()

Thanks for any help!

Upvotes: 2

Views: 499

Answers (1)

Graham T
Graham T

Reputation: 966

Just an issue with the model I created called Subscription and it's hasOne association from User called subscription. This is a reserved word that was creating a collision, and then the QueryBuilder errors noted in the question.

I simply changed the model name that references the subscriptions table to StripeSubscription (include a $table = 'subscriptions' property in the Model), and also the association from User to stripeSubscription.

Then you're able to call the Cashier function, like:

$user->subscribed( $user->stripeSubscription['name'] );

Upvotes: 1

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