CODEWITHSUNDEEP
pythonpython-3.xurlliburlopen
Philippe Talarico
Philippe Talarico

Reputation: 59

Mp3 download urllib.request.urlopen() Time-out

I got a list named href_w with a bunch of mp3 links to download, but when I execute this piece of code, it gives me an error:

# Download file
print(color.BLUE + "\n[*] Downloading requested mp3(s) ..." + color.END)
for link in href_w:
    url = "http://www.mp3c.cc"+link.replace('track','files')
    print("[*] GET "+url)
    req = Request(url, headers={'User-Agent': 'Mozilla/5.0'})
    response = urlopen(req)
    html = response.read()

The error log looks like this:

[*] Downloading requested mp3(s) ...
[*] GET http://www.mp3c.cc/files/88144527_288384031/
Traceback (most recent call last):
  File "mp3spyder.py", line 99, in <module>
    response = urlopen(req)
  File "/usr/lib/python3.4/urllib/request.py", line 153, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib/python3.4/urllib/request.py", line 461, in open
    response = meth(req, response)
  File "/usr/lib/python3.4/urllib/request.py", line 571, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib/python3.4/urllib/request.py", line 493, in error
    result = self._call_chain(*args)
  File "/usr/lib/python3.4/urllib/request.py", line 433, in _call_chain
    result = func(*args)
  File "/usr/lib/python3.4/urllib/request.py", line 676, in http_error_302
    return self.parent.open(new, timeout=req.timeout)
  File "/usr/lib/python3.4/urllib/request.py", line 461, in open
    response = meth(req, response)
  File "/usr/lib/python3.4/urllib/request.py", line 571, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib/python3.4/urllib/request.py", line 499, in error
    return self._call_chain(*args)
  File "/usr/lib/python3.4/urllib/request.py", line 433, in _call_chain
    result = func(*args)
  File "/usr/lib/python3.4/urllib/request.py", line 579, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 502: Bad Gateway

What can I do to do it right?

Upvotes: 1

Views: 831

Answers (2)

Viktor Rzhaksinskii
Viktor Rzhaksinskii

Reputation: 3

I used this script. It takes url of file, reads it and saves it to file. Here is an example with downloaded mp3.

import urllib

url = 'http://www.drowtales.com/download/Path%20to%20Power.mp3'

data = urllib.request.urlopen(url)

f = open('Path to Power.mp3','wb')
f.write(data.read())
f.close()

Upvotes: 0

sorin
sorin

Reputation: 170846

If you get a 502 response from the web server it usually means that their backend is down. You would probably get the same response if you would use curl or wget.

Anyway, you should always try curl or wget in order to debug such problems.

Upvotes: 1

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