Reputation: 3
I'm trying to create a program that encrypts files based on how Nazi Germany's Enigma machine worked, but without the flaw :P.
I have a function that gets a character at n point in a file, but when it returns a return character and I cout << it, it's like it hit enter twice. IE if I loop cout-ing from i++ points in a file the individual lines in the terminal appear separated
by more returns
than one.
Here's the function:
char charN(string pathOf, int pointIn){
char r = NULL;
// NULL so I can tell when it doesn't return a character.
int sizeOf; //to store the found size of the file.
ifstream cf; //to store the Character Found.
ifstream siz; //used later to get the size of the file
siz.open(pathOf.c_str());
siz.seekg(0, std::ios::end);
sizeOf = siz.tellg(); // these get the length of the file and put it in sizeOf.
cf.open(pathOf.c_str());
if(cf.is_open() && pointIn < sizeOf){ //if not open, or if the character to get is farther out than the size of the file, let the function return the error condition: 'NULL'.
cf.seekg(pointIn); // move to the point in the file where the character should be, get it, and get out.
cf.get(r);
cf.close();
}
return r;
}
It works correctly if I use cout << '\n', but what's different about returns from a file and '\n'? Or is there something else I'm missing? I've been googling about but I can't find anything remotely similar to my problem, thanks in advance.
I'm using Code::Blocks 13.12 as my compiler if that matters.
Upvotes: 0
Views: 122
Reputation: 398
Is this is on a windows machine? In windows new lines in text files are representing by \r\n.
It's possible that you are couting each one separately and that the output buffer is creating a new line for each one.
Upvotes: 1