CODEWITHSUNDEEP
xmlxslt
tete
tete

Reputation: 5019

XSLT transformation with keyed Param

I have a piece of xslt file which looks like this:

<xsl:template match="Request">
    <Instrument>
        <IdentifierType>
                 <xsl:value-of select="IDContext"/>
        </IdentifierType>
        <Identifier>
                 <xsl:value-of select="Identifier"/>
        </Identifier>
        <UserDefinedIdentifier>
                 <xsl:value-of select="UserDefinedIdentifier"/>
        </UserDefinedIdentifier>
        <xsl:if test="Param[@Key='Exchange']">
                 <Exchange>
                           <xsl:value-of select="Param[@Key='Exchange']"/>
                 </Exchange>
        </xsl:if>
    </Instrument>
</xsl:template>

And one input xml piece look like this:

<Request>
    <Identifier>XXX</Identifier>
    <IDContext>ISIN</IDContext>
</Request>

Now I want to modify the input xml a little bit, so that the output would be like this:

<Instrument>
    <IdentifierType>ISIN</IdentifierType>
    <Identifier>XXX</Identifier>                            
    <Exchange>EX</Exchange>
</Instrument>

How should I modify the input xml file? Thank you!

Upvotes: 1

Views: 30

Answers (1)

Tim C
Tim C

Reputation: 70648

The XSLT is currently looking for a Param element that is a child of the current Request element that is being matched. This means you would expect your XML to look like this:

<Request>
    <Identifier>XXX</Identifier>
    <IDContext>ISIN</IDContext>
    <Param Key='Exchange'>EX</Param>
</Request>

Having said that, this generates the following output:

<Instrument>
   <IdentifierType>ISIN</IdentifierType>
   <Identifier>XXX</Identifier>
   <UserDefinedIdentifier/>
   <Exchange>EX</Exchange>
</Instrument>

The template you have shown always creates a UserDefinedIdentifier for the Request element, regardless of whether a UserDefinedIdentifier element exists in the XML or not. The only way around this would be to change the XSLT to handle one not being present.

Upvotes: 2

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