Reputation: 4216
I am very new to batch file coding. I am trying to use XCOPY for copying some file. First I used like this:
@echo off
MOVE mypath\abc.txt mypath\abc.txt.0001
XCOPY mypath\abc.txt.bak mypath\abc.txt
pause
This code is working perfectly fine. Then I needed to take some input from user, o I modified the code like this:
@ECHO off
ECHO Starting application.
SET /p path=Enter the path:
SET /p corruptFileName=Enter the corrupted file name:
SET /p oldBackupFileName=Enter the Backup file name to restore:
SET /p correuptedBackupName=Enter the corrupted backup file name:
ECHO Path :
ECHO %path%
ECHO Corrupted file name :
ECHO %corruptFileName%
ECHO Desired Backup file name:
ECHO %correuptedBackupName%
ECHO Backup file name to restore :
ECHO %oldBackupFileName%
MOVE %path%\%corruptFileName% %path%\%correuptedBackupName%
call :waitfor 5000>nul
XCOPY %path%\%oldBackupFileName% %path%\%corruptFileName%
PAUSE
This code is not running. It says that :
The system cannot find the batch label specified - waitfor
'XCOPY' is not recognized as an internal or external command,
operable program or batch file.
Can anyone shed any light in this?
Thanks!
Upvotes: 0
Views: 3210
Reputation: 14304
%path%
is an environment variable that is used to tell the operating system where programs are located. Without it, you have to give the full path to system executables (like xcopy
) before they can be called by name only.
Never overwrite it.
Change the variable name to something else. Anything else.
Upvotes: 2