CODEWITHSUNDEEP
java
user2803555
user2803555

Reputation: 169

How do I iterate through an int

I get an "int cannot be dereferenced" error on this code. It might be because I applied .length on it. What else can I do to iterate through the int?

int num;

System.out.print("Enter a positive integer: ");
num = console.nextInt();

if (num > 0)
for (int i = 0; i < num.length; i++)
System.out.println();

Upvotes: 6

Views: 57137

Answers (4)

Bhavesh Salunke
Bhavesh Salunke

Reputation: 41

  1. Using Integer.toString Method
        int num = 110102;
        String strNum = Integer.toString(num);
        for (int i = 0; i < strNum.length(); i++) {
            System.out.println(strNum.charAt(i));
        }
  1. Using Modulo Operator `
    int num = 1234;
    while(num>0) {
       int remainder = num % 10;
       System.out.println(remainder);
       num = num / 10;    
    }

Upvotes: 1

Michael Rodionov
Michael Rodionov

Reputation: 41

IntStream.range(0, num).forEach(System.out::println);

Upvotes: 4

T3 H40
T3 H40

Reputation: 2436

for (int i = 0; i < num; i++)

Your num already is a number. So your condition will suffice like above.

Example: If the user enters 4, the for statement will evaluate to for (int i = 0; i < 4; i++), running the loop four times, with i having the values 0, 1, 2 and 3

If you wanted to iterate over each digit, you would need to turn your int back to a string first, and then loop over each character in this string:

String numberString = Integer.toString(num);

for (int i = 0; i < numberString.length(); i++){
    char c = numberString.charAt(i);        
    //Process char
}

If you wanted to iterate the binary representation of your number, have a look at this question, it might help you.

Note: though it might not be required, I would suggest you to use {}-brackets around your statement blocks, to improve readability and reduce chance of mistakes like this:

if (num > 0) {
    for (int i = 0; i < num; i++) {
        System.out.println();
    }
}

Upvotes: 10

user2173372
user2173372

Reputation: 513

Try the following code:

import java.util.Scanner;

public class IntExample {
    public static void main(String[] args) {
        Scanner console = new Scanner(System.in);
        System.out.print("Enter a positive integer: ");
        int num = console.nextInt();
        console.close();
        if (num > 0) {
            for (int i = 0; i < num; i++) {
                System.out.println(i);
            }
        }
    }
}

Upvotes: 2

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