CODEWITHSUNDEEP
unixksh
xGen
xGen

Reputation: 554

Passing param to function in ksh script

The parameter passed is changed when printed from inside the function

print "param: $FILEPREFIX" 1>&2;  #return finyear*
func_copy $FILEPREFIX

then in function

function func_copy 
{
    fp=$1
    print "param: $fp" 1>&2;  #returns finyear.scr which is a script file name

what would i be doing wrong here

Upvotes: 0

Views: 2342

Answers (1)

Jonathan Leffler
Jonathan Leffler

Reputation: 754730

When you invoke func_copy $FILEPREFIX and FILEPREFIX contains finyear*, the shell expands the variable and then does wild-card matching, so the name finyear* is changed to finyear.scr in your directory. To avoid the expansion, enclose the name in double quotes:

func_copy "$FILEPREFIX"

(Using double quotes around a variable expansion is usually, but not always, a good idea.)

See the Bash manual on shell expansions for the sequence of operations in Bash. The POSIX shell (sh) has similar rules, and Korn shell will likewise be similar — they all have a common ancestor, the Bourne shell.

Upvotes: 1

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