CODEWITHSUNDEEP
iosswiftavaudioplayer
kmell96
kmell96

Reputation: 1465

Swift AVAudioPlayer Restart from Beginning

I have an AVAudioPlayer stored in a property called "player". When the user clicks a button, it triggers this code:

@IBAction func restartPressed(sender: AnyObject) {
    player.play()
}

The problem is happening when the user clicks the button twice in a row very quickly.

If the sound from the first click is still playing, it seems like the second call is ignored.

Instead, I'd like to either:

a) restart the player from the beginning when the button is clicked a second time; or

b) have two "instances" of the sound playing at the same time.

How would I go about achieving either or both of these options?

Upvotes: 6

Views: 6602

Answers (3)

Laurent Crivello
Laurent Crivello

Reputation: 3931

player.seek(to: .zero)
player.play()

Upvotes: 0

Niall Kiddle
Niall Kiddle

Reputation: 1487

dfri's answer updated for Swift 4

@IBAction func restartPressed(sender: UIButton) {

    if negativePlayer.isPlaying
    {
        negativePlayer.pause()
    }

    negativePlayer.currentTime = 0
    negativePlayer.play()
}

Upvotes: 0

dfrib
dfrib

Reputation: 73206

Answering to "either" part (rather than "both") of these options: (a) how to stop and play the sound from beginning:

@IBAction func restartPressed(sender: AnyObject) {
    if player.playing {
        player.pause()
    }
    player.currentTime = 0
    player.play()
}

Regarding (b): from the Language Ref for AVAudioPlayer:

Using an audio player you can:

...

  • Play multiple sounds simultaneously, one sound per audio player, with precise synchronization.

So you'd need two separate players to simultaneously (off-sync) play two separate sounds, even if both players use the same sound. I'd stick with (a).

Upvotes: 12

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