Reputation: 1419

Concat DataFrame Reindexing only valid with uniquely valued Index objects

I am trying to concat the following dataframes:

df1

                                price   side timestamp
timestamp           
2016-01-04 00:01:15.631331072   0.7286  2   1451865675631331
2016-01-04 00:01:15.631399936   0.7286  2   1451865675631400
2016-01-04 00:01:15.631860992   0.7286  2   1451865675631861
2016-01-04 00:01:15.631866112   0.7286  2   1451865675631866

and:

df2

                                bid     bid_size offer  offer_size
timestamp               
2016-01-04 00:00:31.331441920   0.7284  4000000 0.7285  1000000
2016-01-04 00:00:53.631324928   0.7284  4000000 0.7290  4000000
2016-01-04 00:01:03.131234048   0.7284  5000000 0.7286  4000000
2016-01-04 00:01:12.131444992   0.7285  1000000 0.7286  4000000
2016-01-04 00:01:15.631364096   0.7285  4000000 0.7290  4000000

With

 data = pd.concat([df1,df2], axis=1)

But I get the follwing output:

InvalidIndexError                         Traceback (most recent call last)
<ipython-input-38-2e88458f01d7> in <module>()
----> 1 data = pd.concat([df1,df2], axis=1)
      2 data = data.fillna(method='pad')
      3 data = data.fillna(method='bfill')
      4 data['timestamp'] =  data.index.values#converting to datetime
      5 data['timestamp'] = pd.to_datetime(data['timestamp'])#converting to datetime

/usr/local/lib/python2.7/site-packages/pandas/tools/merge.pyc in concat(objs, axis, join, join_axes, ignore_index, keys, levels, names, verify_integrity, copy)
    810                        keys=keys, levels=levels, names=names,
    811                        verify_integrity=verify_integrity,
--> 812                        copy=copy)
    813     return op.get_result()
    814 

/usr/local/lib/python2.7/site-packages/pandas/tools/merge.pyc in __init__(self, objs, axis, join, join_axes, keys, levels, names, ignore_index, verify_integrity, copy)
    947         self.copy = copy
    948 
--> 949         self.new_axes = self._get_new_axes()
    950 
    951     def get_result(self):

/usr/local/lib/python2.7/site-packages/pandas/tools/merge.pyc in _get_new_axes(self)
   1013                 if i == self.axis:
   1014                     continue
-> 1015                 new_axes[i] = self._get_comb_axis(i)
   1016         else:
   1017             if len(self.join_axes) != ndim - 1:

/usr/local/lib/python2.7/site-packages/pandas/tools/merge.pyc in _get_comb_axis(self, i)
   1039                 raise TypeError("Cannot concatenate list of %s" % types)
   1040 
-> 1041         return _get_combined_index(all_indexes, intersect=self.intersect)
   1042 
   1043     def _get_concat_axis(self):

/usr/local/lib/python2.7/site-packages/pandas/core/index.pyc in _get_combined_index(indexes, intersect)
   6120             index = index.intersection(other)
   6121         return index
-> 6122     union = _union_indexes(indexes)
   6123     return _ensure_index(union)
   6124 

/usr/local/lib/python2.7/site-packages/pandas/core/index.pyc in _union_indexes(indexes)
   6149 
   6150         if hasattr(result, 'union_many'):
-> 6151             return result.union_many(indexes[1:])
   6152         else:
   6153             for other in indexes[1:]:

/usr/local/lib/python2.7/site-packages/pandas/tseries/index.pyc in union_many(self, others)
    959             else:
    960                 tz = this.tz
--> 961                 this = Index.union(this, other)
    962                 if isinstance(this, DatetimeIndex):
    963                     this.tz = tz

/usr/local/lib/python2.7/site-packages/pandas/core/index.pyc in union(self, other)
   1553                 result.extend([x for x in other._values if x not in value_set])
   1554         else:
-> 1555             indexer = self.get_indexer(other)
   1556             indexer, = (indexer == -1).nonzero()
   1557 

/usr/local/lib/python2.7/site-packages/pandas/core/index.pyc in get_indexer(self, target, method, limit, tolerance)
   1890 
   1891         if not self.is_unique:
-> 1892             raise InvalidIndexError('Reindexing only valid with uniquely'
   1893                                     ' valued Index objects')
   1894 

InvalidIndexError: Reindexing only valid with uniquely valued Index objects

I have removed additional columns and removed duplicates and NA where there could be a conflict - but I simply do not know what's wrong.

Upvotes: 127

Answers (16)

Srikrishna Krishnarao Srinivas

Reputation: 55

df1 = pd.DataFrame.from_dict({'A':[1,2,3], 'B':[110,120,230]})
df2 = pd.DataFrame.from_dict({'B':[11,12,23], 'C':[10,11,12]})
df2.rename(columns={'C':'B'}, inplace=True)
pd.concat([df1,df2])

InvalidIndexError: Reindexing only valid with uniquely valued Index objects

The above code will replicate the error when concatenating rows of dataframe. The reason the error occurs is because, there are two columns in df2 with the same name 'B'

    A   B
0   1   110
1   2   120
2   3   230

    B   B
0   11  10
1   12  11
2   23  12

Upvotes: 0

Filipe Papa

Reputation: 1

Happened the same with me, but then I noticed that my index (datetime) has different last dates. When I fixed the date using the same timeframe interval for both dataframes the pd.concat() worked fine.

Upvotes: 0

s510

Reputation: 2822

The indexes of your two dataframes don't match.

When pandas is performing concat operation horizontally (axis=1) it tries to find rows with same indexes and join them horizontally. So row with index 1 from df1 will be matched with row with index 1. Therefore reset index in either one of them or both if both have troubled indexes.

pd.concat([df1.reset_index(drop=True), df2], axis=1)

pd.concat([df1.reset_index(drop=True), df2.reset_index(drop=True), axis=1])

Upvotes: 4

jawad.shaik shaik

Reputation: 21

below solution would work if you are concat is using axis=0, which means you want to append rows not columns

reason : one or both of your dataframes might have duplicate columns df1 columns could be A, B, C , C df2 columns could be B, D

in this case A has duplicate column C, and for this reason you might get this error. Drop one of the C column in df1 and hopefully issue will be resolved

df1['C'].is_unique

Upvotes: 0

Andru

Reputation: 23

The problem for me was duplicate column labels, just as many others here mentioned it. To keep only the first column for duplicates I used below:

df=df.T[~df.T.index.duplicated(keep='first')].T

Upvotes: 2

Jane Kathambi

Reputation: 935

This is because you have duplicated columns. Before concatenating drop duplicated columns in each DataFrame as follows:

df = df.loc[:,~df.columns.duplicated()].reset_index(drop=True)

Upvotes: 5

shiva

Reputation: 2699

Answers here helped but concat worked fine for me in some cases even where duplicate columns were present. However, in some cases it didn't work and raised the InvalidIndexError.

It turned out that it works fine if order of duplicate columns is same but raises an error if order of duplicate columns is different.

Example where it works fine:

df = pd.DataFrame({'a': [1, 2, 3], 'b': [5, 6, 7], 'c': [9, 10, 11]})
df1 = pd.DataFrame({'a': [12], 'b': [13], 'c': [14]})
df.rename(columns={
    'c': 'b'
}, inplace=True)
df1.rename(columns={
    'c': 'b'
}, inplace=True)
print(pd.concat([df, df1]))

Output:
    a   b   b
0   1   5   9
1   2   6  10
2   3   7  11
0  12  13  14

Example where it doesn't work:

df = pd.DataFrame({'b': [1, 2, 3], 'a': [5, 6, 7], 'c': [9, 10, 11]})
df1 = pd.DataFrame({'a': [12], 'b': [13], 'c': [14]})
df.rename(columns={
    'c': 'b'
}, inplace=True)
df1.rename(columns={
    'c': 'b'
}, inplace=True)
print(pd.concat([df, df1]))

Output:
pandas.errors.InvalidIndexError: Reindexing only valid with uniquely 
valued Index objects

Upvotes: 1

Vini Machado

Reputation: 21

This happened to me when I was trying to concat two dataframes that have duplicated column names!

Let's say that I want to remove the first duplicated column:

duplicated_column = 'column'

df_tmp = df[duplicated_column].T
df_tmp = df_tmp.iloc[1: , :]

df = df.drop([duplicated_column], axis=1)
df = pd.concat([df, df_tmp.T], axis=1)

Upvotes: 2

Darina

Reputation: 1632

This post comes up top when you search for the error but the answers are not complete, so let me add mine. There is another reason this error can happen: If you have duplicate columns in your data frames, you will not be able to concatenate and raise this. In fact, even in the original question there are two columns called timestamp. So it will be better to check if len(df.columns) == len(set(df.columns)) for all the data frames you are trying to concatenate.

Upvotes: 32

Sayyor Y

Reputation: 1314

Same Indices Between the Two DFs

Another reason for this issue might be that df1 and df2 might have the same indices, between each other. For example, both the dfs might have the same index idx1.

To check if this is the issue, you can see if the following outputs not an empty list:

print([org_name for org_name in cum_df.index if org_name in df_from_2002.index])

My suggested solution then would be to rename the indices (so df1 would keep having idx1 and you would change idx1 to idx2 in df2) and after concatenating (df1 = pd.concat([df1, df2])), combine the two indices (in case you need to get the sum of them) with this code:

df1.iloc[idx1] = df1.iloc[[idx1, idx2]].sum()

and then remove idx2:

df1.drop([idx2], inplace=True)

Upvotes: 3

Miguel Gutierrez

Reputation: 159

This happens also when you have duplicates in the columns names.

Upvotes: 4

Angel

Reputation: 2865

Duplicated column names!

In my case the problem was because I had duplicated column names.

Upvotes: 145

Xieyi

Reputation: 1328

As a complement of Nicholas Morley's answer, when you find even this not works:

df = df.reset_index(drop=True)

You should check whether the columns are unique. When they are not, even reseting index not works. Duplicated columns should be removed first to make it works.

Upvotes: 8

Yapi

Reputation: 314

best solution from this page: https://pandas.pydata.org/pandas-docs/version/0.20/merging.html

df = pd.concat([df1, df2], axis=1, join_axes=[df1.index])

Upvotes: -1

Nicholas Morley

Reputation: 4240

You can mitigate this error without having to change your data or remove duplicates. Just create a new index with DataFrame.reset_index:

df = df.reset_index()

The old index is kept as a column in your dataframe, but if you don't need it you can do:

df = df.reset_index(drop=True)

Some prefer:

df.reset_index(inplace=True, drop=True)

Upvotes: 117

unutbu

Reputation: 879401

pd.concat requires that the indices be unique. To remove rows with duplicate indices, use

df = df.loc[~df.index.duplicated(keep='first')]

import pandas as pd
from pandas import Timestamp

df1 = pd.DataFrame(
    {'price': [0.7286, 0.7286, 0.7286, 0.7286],
     'side': [2, 2, 2, 2],
     'timestamp': [1451865675631331, 1451865675631400,
                  1451865675631861, 1451865675631866]},
    index=pd.DatetimeIndex(['2000-1-1', '2000-1-1', '2001-1-1', '2002-1-1']))


df2 = pd.DataFrame(
    {'bid': [0.7284, 0.7284, 0.7284, 0.7285, 0.7285],
     'bid_size': [4000000, 4000000, 5000000, 1000000, 4000000],
     'offer': [0.7285, 0.729, 0.7286, 0.7286, 0.729],
     'offer_size': [1000000, 4000000, 4000000, 4000000, 4000000]},
    index=pd.DatetimeIndex(['2000-1-1', '2001-1-1', '2002-1-1', '2003-1-1', '2004-1-1']))


df1 = df1.loc[~df1.index.duplicated(keep='first')]
#              price  side         timestamp
# 2000-01-01  0.7286     2  1451865675631331
# 2001-01-01  0.7286     2  1451865675631861
# 2002-01-01  0.7286     2  1451865675631866

df2 = df2.loc[~df2.index.duplicated(keep='first')]
#                bid  bid_size   offer  offer_size
# 2000-01-01  0.7284   4000000  0.7285     1000000
# 2001-01-01  0.7284   4000000  0.7290     4000000
# 2002-01-01  0.7284   5000000  0.7286     4000000
# 2003-01-01  0.7285   1000000  0.7286     4000000
# 2004-01-01  0.7285   4000000  0.7290     4000000

result = pd.concat([df1, df2], axis=0)
print(result)
               bid  bid_size   offer  offer_size   price  side     timestamp
2000-01-01     NaN       NaN     NaN         NaN  0.7286     2  1.451866e+15
2001-01-01     NaN       NaN     NaN         NaN  0.7286     2  1.451866e+15
2002-01-01     NaN       NaN     NaN         NaN  0.7286     2  1.451866e+15
2000-01-01  0.7284   4000000  0.7285     1000000     NaN   NaN           NaN
2001-01-01  0.7284   4000000  0.7290     4000000     NaN   NaN           NaN
2002-01-01  0.7284   5000000  0.7286     4000000     NaN   NaN           NaN
2003-01-01  0.7285   1000000  0.7286     4000000     NaN   NaN           NaN
2004-01-01  0.7285   4000000  0.7290     4000000     NaN   NaN           NaN

Note there is also pd.join, which can join DataFrames based on their indices, and handle non-unique indices based on the how parameter. Rows with duplicate index are not removed.

In [94]: df1.join(df2)
Out[94]: 
             price  side         timestamp     bid  bid_size   offer  \
2000-01-01  0.7286     2  1451865675631331  0.7284   4000000  0.7285   
2000-01-01  0.7286     2  1451865675631400  0.7284   4000000  0.7285   
2001-01-01  0.7286     2  1451865675631861  0.7284   4000000  0.7290   
2002-01-01  0.7286     2  1451865675631866  0.7284   5000000  0.7286   

            offer_size  
2000-01-01     1000000  
2000-01-01     1000000  
2001-01-01     4000000  
2002-01-01     4000000  

In [95]: df1.join(df2, how='outer')
Out[95]: 
             price  side     timestamp     bid  bid_size   offer  offer_size
2000-01-01  0.7286     2  1.451866e+15  0.7284   4000000  0.7285     1000000
2000-01-01  0.7286     2  1.451866e+15  0.7284   4000000  0.7285     1000000
2001-01-01  0.7286     2  1.451866e+15  0.7284   4000000  0.7290     4000000
2002-01-01  0.7286     2  1.451866e+15  0.7284   5000000  0.7286     4000000
2003-01-01     NaN   NaN           NaN  0.7285   1000000  0.7286     4000000
2004-01-01     NaN   NaN           NaN  0.7285   4000000  0.7290     4000000

Upvotes: 70

Concat DataFrame Reindexing only valid with uniquely valued Index objects

Answers (16)

The indexes of your two dataframes don't match.

Same Indices Between the Two DFs

Duplicated column names!

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