CODEWITHSUNDEEP
cstringstdout
untitled
untitled

Reputation: 409

How can I print directly a number as a string?

printf("%s", 0x216f6c6c6548); // "Hello!" reversed

It should print "Hello!" but it doesn't. I expected the same result of:

long long ll = 0x216f6c6c6548;
printf("%s", &ll);

or

printf("%s", "Hello!");

Is it possible to print a number as a string?

UPDATE

Is it possible to print directly a number as a string?

Upvotes: 0

Views: 130

Answers (2)

chux
chux

Reputation: 154280

After accept answer

Easy to print directly. Use a compound literal to form the string.

#include <stdio.h>
#define SBprint(x) ((char [8+1]){ \
    1ULL*x>>0 , 1ULL*x>> 8, 1ULL*x>>16, 1ULL*x>>24, \
    1ULL*x>>32, 1ULL*x>>40, 1ULL*x>>48, 1ULL*x>>56, 0})


int main(void) {
  printf("%s", SBprint(0x216f6c6c6548));
  printf("%s", SBprint(0x65726120776F480A));
  printf("%s", SBprint(0x0A3F756F7920));
}

Output

Hello!
How are you?

If your compiler use little endian, even simpler.

#define SBprint(x) ((union {long long ll[2]; char s[sizeof(long long)+1]; }){ {x, 0} }).s

Upvotes: 2

Doug Currie
Doug Currie

Reputation: 41200

You have to extract the characters from the number:

print_ull_as_str (unsigned long long ll)
{
    while (ll != 0) { printf("%c", (char )(ll & 0xffu)); ll >>= 8; }
}

Upvotes: 6

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