Reputation: 39
Can someone give me the solution for the following code puzzle? A solution was given but could be more than one solution.
// this code compiles
IAnimal animal= new Dog();
animal.Eat();
// this code doesn't compile
Dog animal = new Dog();
animal.Eat();
How should the class definition look like so that the above code blocks, in separate scopes, compile(first one) and don't compile(second one) ?
Upvotes: 2
Views: 188
Reputation: 205629
The obvious solution (IAnimal
being interface and Dog
being a class implementing that interface explicitly) is already provided in other answers.
Here are some other ways I can think of.
All they are based on IAnimal
being a (poorly named) class like this
public class IAnimal
{
public void Eat() { }
}
(A) Solution based on class defining an implicit conversion operator (note that defining a conversion from class to interface is prohibited, that's why it's important IAnimal
to be a class/struct)
public class Dog
{
public static implicit operator IAnimal(Dog dog) { return new IAnimal(); }
}
causes the following compile error in the second snippet:
Error CS1061: 'Dog' does not contain a definition for 'Eat' and no extension method 'Eat' accepting a first argument of type 'Dog' could be found (are you missing a using directive or an assembly reference?)
(B) Solutions based on base method hiding. Although in C# we can't hide the base method by providing in a derived class another method with different signature (because it will be treated as overload), we can do that by using a field, property or event with incompatible signature.
For instance
public class Dog : IAnimal
{
new public event Action Eat;
}
generates
Error CS0070: The event 'Dog.Eat' can only appear on the left hand side of += or -= (except when used from within the type 'Dog')
or
public class Dog : IAnimal
{
new public Action<int> Eat;
}
generates
Error CS7036: There is no argument given that corresponds to the required formal parameter 'obj' of 'Action'
Upvotes: 2
Reputation: 35280
The error on the second line is caused because the class Dog
explicitly implements the IAnimal
interface like this:
class Dog : IAnimal
{
void IAnimal.Eat()
{
throw new NotImplementedException();
}
}
In this case, you get the compile error on your second line because you cannot call Eat
unless you're working with an instance of IAnimal
because it's essentially a private method in Dog
.
To fix the error, you either need to cast your instance back to an IAnimal
like I showed you above, or you can implicitly implement the interface like this instead:
class Dog : IAnimal
{
public void Eat()
{
throw new NotImplementedException();
}
}
Upvotes: 3
Reputation: 12846
You can achieve this by using explicit interface implementation:
class Dog : IAnimal {
void IAnimal.Eat(){
//do stuff
}
}
As opposed to implicit interface implementation:
class Dog : IAnimal {
public void Eat(){
//do stuff
}
}
Upvotes: 4
Reputation: 4833
public interface IAnimal
{
void Eat();
}
public class Dog : IAnimal
{
void IAnimal.Eat() { }
}
IAnimal animal = new Dog();
animal.Eat(); // <---- OK
Dog animal2 = new Dog();
animal2.Eat(); // <---- COMPILE ERROR
Upvotes: 3