CODEWITHSUNDEEP
swiftcharacter-encoding
Rodrigo
Rodrigo

Reputation: 12683

How dynamically create a Character in Swift 2.1

I have a file with this string:

N\u00e3o informado

Than I read it and put in a variable

let myString =  NSString(contentsOfFile: filename, encoding: NSUTF8StringEncoding)
print(mystring) // get "N\u00e3o informado"

Then I want to convert the \u00e3 to your unicode value = ã. I read in Swift Book this line:

let text = "Voulez-vous un caf\u{65}\u{301}?"

And I tried create the same thing dynamicaly, but it didn't worked:

let substring = "00e3"
dinamic = "N\u{\(substring)}o informado"   //This produce the equivalent
print(dinamic)  // get "N\u{00e3}o informado" but I want "Não informado"

In the same way, this not work

let code = "00e3"
let caracter = Character("\u{\(code)}")   //compile error
let caracter = Character("\\u{\(code)}")  //runtime error
let number = 00e3
let caracter = Character(number)    //compile error
let caracter = Character("\u{00e3}") //This work, but isn't dinamic

How can I do this?

Upvotes: 1

Views: 67

Answers (1)

vacawama
vacawama

Reputation: 154603

First convert your String to an Int telling Int that it is in base 16, then create a UnicodeScalar from the Int, and finally create the Character from the UnicodeScalar:

let code = "00e3"
let character = Character(UnicodeScalar(Int(code, radix: 16)!))

If you'd prefer to have a String instead of a Character, then:

let string = String(UnicodeScalar(Int(code, radix: 16)!))

Upvotes: 1

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