Reputation: 662
I feel like I'm missing something terribly obvious, but I cannot seem to find the array pair with the lowest value.
I have an int[,] worldMapXY
where a 2D map is stored, say worldMapXY[0,0]
through worldMapXY[120,120]
. All values of map's array are 1 (wall\invalid) or 0 (path/valid).
I'm writing a method that will find coordinates in one of the eight cardinal directions to create a spawn point. So I also have int[,] validSpotArr
which has a subset of bounds of the map closest to the direction I'm setting the spawn. The values for wall/invalid locations are set to 9999
, the values for path/valid locations are set to (x + y)
. This is all specific to the bottom left corner, nearest to [0,0]
, hence "BL" or "Bottom Left"
case "BL":
for (int x = (int)border + 1; x < worldX + (int)border / 4; x++)
{
for (int y = (int)border + 1; y < worldY + (int)border / 4; y++)
{
if (worldMapXY[x,y] = 0)
{
validSpotArr[x,y] = x + y;
}
else
{
validSpotArr[x,y] = 9999;
}
}
}
What I can't quite wrap my head around is how to determine the coordinates/index of validSpotArr
with the lowest value in such a way that I could pass those as separate x and y coordinates to another function (to set the spawn point). I suspect there's a lambda operator that may help, but I literally don't understand lambdas. Clearly that needs to be my next point of study.
E.g. - if validSpotArr[23, 45] = 68
, and 68 is the lowest value, how do I set x=23 and y=45?
Edit: I tried messing around with something like this, but it isn't right:
Array.IndexOf(validSpotArr, validSpotArr.Min());
Upvotes: 0
Views: 739
Reputation: 568
While not precisely an answer to your question, in a strictly given situation I'd probably go for finding those from within the cycles, i.e.
int minValidSpot = int.MaxValue, minX, minY;
for (int x = (int)border + 1; x < worldX + int(border) / 4; x++)
{
for (int y = (int)border + 1; y < worldY + int(border) / 4; y++)
{
if (worldMapXY[x,y] = 0)
{
validSpotArr[x,y] = x + y;
}
else
{
validSpotArr[x,y] = 9999;
}
if ( minValidSpot > validSpotArr[x,y] )
{
minValidSpot = validSpotArr[x,y];
minX = x;
minY = y;
}
}
}
Other than that, if looking for some kind of more universal solution, I'd probably just flatten that array, the maths for index conversion (nD<=>1D) are pretty simple.
Upvotes: 1