CODEWITHSUNDEEP
python
HenryDev
HenryDev

Reputation: 4983

how to loop through 3 lists and get 3 columns in Python?

I have three lists list1 is "Car Models" list2 is "price per galon (mpg)" and list3 is "total price for one year". I'm able to loop through the 3 columns, but I don't know how to get 3 columns one after the other. Please someone help me. Thank you in advance!!

Heres my code:

modelName = ['Toyota', 'Nissan',  'Honda']
fuelEfficiency = [15.0, 20.0, 30.0]
for i in range(len(modelName)):
print (modelName[i])

for i in range(len(fuelEfficiency )):
print (fuelEfficiency[i])

priceGas = 2.41

totalCost1 = (10000 * priceGas)/15.0
totalCost2 = (10000 * priceGas)/20.0
totalCost3 = (10000 * priceGas)/30.0

print (totalCost1)
print (totalCost2)
print (totalCost3)

The output I want is this:

MODEL    COST(MPG) TOTALCOST
Toyota   15.0      1606.66  
Nissan   20.0      1205.0
Honda    30.0      803.33

Upvotes: 0

Views: 3160

Answers (6)

Kyle Fritz
Kyle Fritz

Reputation: 86

Because every column that you want has the same amount of items, you only need to use one for loop. You also need to make a totalCost array for this to work.

modelName = ['Toyota', 'Nissan',  'Honda']
fuelEfficiency = [15.0, 20.0, 30.0]

priceGas = 2.41

totalCost = [0, 0, 0] # Filler values
totalCost[0] = (10000 * priceGas)/15.0
totalCost[1] = (10000 * priceGas)/20.0
totalCost[2] = (10000 * priceGas)/30.0


for i in range(len(modelName)):
    print modelName[i], fuelEfficiency[i], totalCost[i]

This should work

Upvotes: 2

Hackaholic
Hackaholic

Reputation: 19753

Try this:

modelName = ['Toyota', 'Nissan',  'Honda']
fuelEfficiency = [15.0, 20.0, 30.0]
priceGas = 2.41
totalCost1 = (10000 * priceGas)/15.0
totalCost2 = (10000 * priceGas)/20.0      # totalCost = list(map(lambda x: (10000*priceGas)/x, fuelEfficiency))
totalCost3 = (10000 * priceGas)/30.0
totalCost = [totalCost1, totalCost2, totalCost3]

print("Model", "Cost(MPG)", "TOTALCOST")
for x in range(3):
    print(modelName[x], fuelEfficiency[x], totalCost[x])

for more better format, use format

Upvotes: 2

python
python

Reputation: 4521

Since you are talking about looping parallel, I would highly recommend to use zip. See the below example! 

modelName = ['Toyota', 'Nissan',  'Honda']
fuelEfficiency = [15.0, 20.0, 30.0]
priceGas = 2.41
totalCost1 = (10000 * priceGas)/15.0
totalCost2 = (10000 * priceGas)/20.0
totalCost3 = (10000 * priceGas)/30.0
totalcost = [totalCost1, totalCost2, totalCost3]

print ("Model", "Cost(MPG)", "TOTALCOST")
for i in zip(modelName, fuelEfficiency, totalcost):
    print (" ".join(map(str, list(i))))

OUTPUT : I am running Python3.4

Model Cost(MPG) TOTALCOST
Toyota 15.0 1606.6666666666667
Nissan 20.0 1205.0
Honda 30.0 803.3333333333334

Upvotes: 1

sudheesh shetty
sudheesh shetty

Reputation: 368

You can Try this.

modelName = ['Toyota', 'Nissan',  'Honda']
fuelEfficiency = [15.0, 20.0, 30.0]
for i in range(len(modelName)):
    print (modelName[i])

for i in range(len(fuelEfficiency )):
    print (fuelEfficiency[i])

priceGas = 2.41

totalCost=[0]*len(fuelEfficiency)

for i in range(len(fuelEfficiency)):
    totalCost[i]=(10000 * priceGas)/fuelEfficiency[i]


print "Model     Cost      Totalcost"
for i in range(len(fuelEfficiency)):
    print modelName[i],fuelEfficiency[i],totalCost[i]

Arrange the output according to your need.

Upvotes: 1

SPKoder
SPKoder

Reputation: 1903

You can use pandas for working with data in a table-like (aka DataFrame) structure.

import pandas as pd

modelName = ['Toyota', 'Nissan',  'Honda']
fuelEfficiency = [15.0, 20.0, 30.0]
priceGas = 2.41

df = pd.DataFrame({'MODEL': modelName, 'COST(MPG)': fuelEfficiency})
df['TOTALCOST'] = (10000 * priceGas) / df['COST(MPG)']

print df[['MODEL', 'COST(MPG)', 'TOTALCOST']].to_string(index=False)

This has the advantage that if you end up wanting to do more advanced data manipulation or formatting, there are a lot of convenient options in the pandas.DataFrame data structure.

Upvotes: 1

Ahasanul Haque
Ahasanul Haque

Reputation: 11144

I think below solution is more pythonic

modelName = ['Toyota', 'Nissan',  'Honda']
fuelEfficiency = [15.0, 20.0, 30.0]
priceGas = 2.41

totalcost = map(lambda x:(10000 * priceGas)/x,fuelEfficiency)

for a,b,c in zip(modelName,fuelEfficiency,totalcost ):
    print a,b ,c

Upvotes: 1

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