CODEWITHSUNDEEP
ccasting
macabeus
macabeus

Reputation: 4592

Generalized type of array in parameter of function

I have the function:

void print_sum(int list[], int length) {
    float sum = 0.0;
    int i;
    for (i = 0; i < length; i++) {
        sum += (float) list[i];
    }
    printf("Sum: %0.2f\n", sum);
}

I want, in the same function, can receive a array of int or a array of float, for example. How I can make it?

Upvotes: 1

Views: 35

Answers (1)

user4098326
user4098326

Reputation: 1742

In C++, this could be done with a template. But in C, you can accomplish something like this with macros. One way is to replace the function with a macro:

#define PRINT_SUM(list,type,format,length) do{ \
      type sum = 0;                            \
      int i;                                   \
      for (i = 0; i < length; i++) {           \
          sum += (type) list[i];               \
      }                                        \
      printf("Sum: " format "\n", sum);        \
    }while(0)

To use this, write something like PRINT_SUM(a,float,"%0.2f",3);.

The other way is to define a macro that defines a function which receive a list of a given type:

#define DEFINE_PRINT_SUM(name,type,format) void name(type list[], int length) { \
     type sum = 0.0;                                                            \
     int i;                                                                     \
     for (i = 0; i < length; i++) {                                             \
       sum += (type) list[i];                                                   \
     }                                                                          \
     printf("Sum: "format"\n", sum);                                            \
   }

Then you can define a float version of print_sum with DEFINE_PRINT_SUM(print_sum_float,float,"%0.2f").

Upvotes: 3

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