CODEWITHSUNDEEP
pythonpython-3.x
huihan
huihan

Reputation: 43

Compare a variable to every element of an array

I am trying to compare a variable to the values that are stored in an array. The values in the array are extracted out from a csv file. If the values of the array are equal to the variable it will print out true.

import csv

array=[]

values = csv.reader(open('SampleEEG data Insight-1-30.11.15.17.36.16.csv', 'r'),       
                    delimiter=',',
                    quotechar='|')
for row in values:
    array.append(row[5])

number= 4200

for a in array:
    if number == a:
        print ('True')
print ('False')

The code only compares one value in the array and returns a false. How do I compare all the values in the array to the variable?

Upvotes: 1

Views: 16624

Answers (4)

user3503711
user3503711

Reputation: 2056

Because it is exiting from the loop after it hits the first true value. Use the following code: 

   for i in array:
        if number == i:
            print ('True')
        else:
            print ('False')

Upvotes: 0

Sнаđошƒаӽ
Sнаđошƒаӽ

Reputation: 17552

From what I could figure out from your comment, this is probably what you are looking for:

array=[]

with open('SampleEEG data Insight-1-30.11.15.17.36.16.csv', 'r') as file:
    lines = [line.split() for line in file.readlines()]


for line in lines:
    try:
        array.append(float(line[5]))
    except ValueError:
        pass

number= 4200

for a in array:
    if number == a:
        print ('True')
print ('Done, all checked')

Upvotes: 0

Harsha Biyani
Harsha Biyani

Reputation: 7268

You can use all() - builtin function

all (number == a for a in array)

Upvotes: 0

Brendan Abel
Brendan Abel

Reputation: 37509

Use the all function with list comprehensions

number = 10
array = [1, 2, 3, 4]

print( all(number == a for a in array) )
# False

array = [10, 10, 10, 10]
print( all(number == a for a in array) )
# True

Upvotes: 3

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