CODEWITHSUNDEEP
rubyregex
rahrahruby
rahrahruby

Reputation: 693

Get line matching a regular expression

I have the following string in a file called mib.txt:

[name=1.3.6.1.2.1.1.5.0, value=myrouter.ad.local (OCTET STRING)]

name the following code:

f = File.read("/temp/mib.txt")
name = f.match(/1.3.6.1.2.1.1.5.0/)
puts "device name is #{name}"

It returns the 1.3.6.1.2.1.1.5.0 just like I asked it to, but what I really want is to find the string the contains 1.3.6.1.2.1.1.5.0 and parse out the value myrouter.

Upvotes: 0

Views: 326

Answers (2)

hgf
hgf

Reputation: 575

You must extend your regex to catch the value inside a regex group.

s = File.read("/temp/mib.txt")
m = s.match /\[name=1.3.6.1.2.1.1.5.0, value=([\S]+) \(OCTET STRING\)/
puts "device name is #{m[1]}"

Upvotes: 1

Chris Bunch
Chris Bunch

Reputation: 89903

You always could use scan:

>> name = f.scan(/1.3.6.1.2.1.1.5.0, value=(\w+)/).flatten.to_s
=> "myrouter"

If you want the ad.local part as well, then instead do:

>> name = f.scan(/1.3.6.1.2.1.1.5.0, value=([\w\.]+)/).flatten.to_s
=> "myrouter.ad.local"

Upvotes: 1

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