CODEWITHSUNDEEP
pythonipython
yalis
yalis

Reputation: 1518

Why is IPython.display.Image not showing in output?

I have a cell that looks like this:

from IPython.display import Image
i = Image(filename='test.png')
i
print("test")

The output is just:

test

I don't see the image in the output. I checked to see that the file exists (anyway, if it did not exist, you get an error).

Any clues?

Upvotes: 10

Views: 36725

Answers (3)

Roland Puntaier
Roland Puntaier

Reputation: 3511

After looking into the code, I can say, that under Windows, as of IPython 7.1.0, this is only supported with %matplotlib inline, which does not work under the interactive IPython shell.

There is extra code in Jupyter. The following example works with

  • jupyter qtconsole
  • jupyter notebook
  • jupyter console in principle, but only via external program, and then for the example the temporary file got deleted

def test_display(): import pyx c = pyx.canvas.canvas() circle = pyx.path.circle(0, 0, 2) c.stroke(circle, [pyx.style.linewidth.Thick,pyx.color.rgb.red]) return c display(test_display())

Upvotes: 0

Arthur Julião
Arthur Julião

Reputation: 869

I had the same problem. Matplot lib expects to show figs outside the command line, for example in the GTK or QT.

Use this: get_ipython().magic(u'matplotlib inline')

It will enable inline backend for usage with IPython notebook.

See more here and here.

Upvotes: 2

minrk
minrk

Reputation: 38598

creating the image with

i = Image(filename='test.png')

only creates the object to display. Objects are displayed by one of two actions:

  1. a direct call to IPython.display.display(obj), e.g.

    from IPython.display import display
display(i)

  2. the displayhook, which automatically displays the result of the cell, which is to say putting i on the last line of the cell. The lone i in your example doesn't display because it is not the last thing in the cell. So while this doesn't display the image:

    i = Image(filename='test.png')
i
print("test")

    This would:

    i = Image(filename='test.png')
print("test")
i

Upvotes: 15

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