CODEWITHSUNDEEP
pythonpython-3.x
Harry
Harry

Reputation: 129

Finding Words In List

I am trying to make something that finds where a word is in a list and then tells you where it is here is what i have so far:

whenAppears = 0
when = []
i = 0
phrase = str(input("What sentence? "))
phrase = phrase.lower()
phrase = phrase.split()
print(phrase)
wordel = str(input("What single word would you like to find? "))
wordel = wordel.lower()
if wordel in phrase:
    print ("That word is in the phrase, there are",phrase.count(wordel),wordel+"('s)""in the sentence")
for word in phrase:
    whenAppears += 1
    if wordel == phrase[i]:
        when.append(whenAppears)
print ("The word",wordel,"is in the slot",when)

no matter what i put in it says the word is in slot 1 and any other slots, i cant think of any ways to pic this, please help :D

Upvotes: 0

Views: 82

Answers (3)

Anton Protopopov
Anton Protopopov

Reputation: 31662

You could rewrite your code more efficiently with list.index:

phrase = str(input("What sentence? ")).lower().split()
print(phrase)
wordel = str(input("What single word would you like to find? ")).lower()
if wordel in phrase:
    print ("That word is in the phrase, there are",phrase.count(wordel), wordel+"('s)""in the sentence")
    print ("The word",wordel,"is in the slot", phrase.index(wordel))

Upvotes: 0

timgeb
timgeb

Reputation: 78650

Put whenAppears += 1 after the if block. Change wordel == phrase[i] to wordel == word. Delete the line i = 0.

Corrected code:

whenAppears = 0
when = []
phrase = str(input("What sentence? "))
phrase = phrase.lower()
phrase = phrase.split()
print(phrase)
wordel = str(input("What single word would you like to find? "))
wordel = wordel.lower()
if wordel in phrase:
    print ("That word is in the phrase, there are",phrase.count(wordel),wordel+"('s)""in the sentence")
for word in phrase:
    if wordel == word:
        when.append(whenAppears)
    whenAppears += 1
print ("The word",wordel,"is in the slot",when)

You could make your code nicer with comprehensions and enumerate, but these are the errors you definitely have to fix.

Upvotes: 1

k4ppa
k4ppa

Reputation: 4667

You use the loop in an incorrect way. You must compare wordel with word, because any time you loop over phrase, the value is stored in word.

for word in phrase:
    whenAppears += 1
    if wordel == word:
        when.append(whenAppears)

Upvotes: 0

Related Questions