CODEWITHSUNDEEP
iphonecocoa-touchnsdate
ohho
ohho

Reputation: 51951

How to calculate first NSDate of current week?

i.e.:

  NSDate *firstDayOfWeek = [[NSDate date] firstDayOfWeek];

for example, today is Aug 19, I'd want to get a NSDate of 2010-08-15 12:00am from above line of code. Thanks!

Upvotes: 14

Views: 10416

Answers (8)

Dare2dream
Dare2dream

Reputation: 76

For Swift 4.1:

extension Date {
  var startOfWeek: Date? {
        let calendar = Calendar(identifier: .gregorian)
        return calendar.date(from: calendar.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self))
    }
}

Upvotes: 1

Rudolf Adamkovič
Rudolf Adamkovič

Reputation: 31486

Why so complicated? :)

func firstDateOfWeekWithDate(date: NSDate) -> NSDate {

    var beginningOfWeek: NSDate?

    calendar.rangeOfUnit(.WeekOfYear, startDate: &beginningOfWeek, interval: nil, forDate: date)

    return beginningOfWeek!

}

Upvotes: 22

Kevin Marlow
Kevin Marlow

Reputation: 901

This has already been answered, but as Wolfgang has pointed out, there is a bug in the accepted answer. If the first weekday is set as a greater date than the NSDate in question, the result will be incorrect. Here is a complete solution that works for all possible firstWeekday values (the example uses Monday).

- (NSDate *)weekOfDate:(NSDate *)originalDate
{
    NSCalendar *currentCal = [NSCalendar currentCalendar];
    [currentCal setFirstWeekday:2]; // Sun = 1, Mon = 2, etc.

    NSDateComponents *weekdayComponents = [currentCal components:NSCalendarUnitWeekday fromDate:originalDate];

    // Calculate the number of days to subtract and create NSDateComponents with them.
    NSDateComponents *componentsToSubtract = [[NSDateComponents alloc] init];
    NSInteger daysToSubtract = (([weekdayComponents weekday] - [currentCal firstWeekday]) + 7) % 7;
    [componentsToSubtract setDay:-1 * daysToSubtract];

    return [currentCal dateByAddingComponents:componentsToSubtract toDate:originalDate options:0];
}

Upvotes: 2

Roman Ralovets
Roman Ralovets

Reputation: 131

The simplest solution:

func firstDayOfWeek(date: NSDate) -> NSDate {
  let calendar = NSCalendar.currentCalendar()
  var dateComponents = calendar.components(.CalendarUnitYear | .CalendarUnitMonth | .CalendarUnitWeekOfMonth, fromDate: date)
  dateComponents.weekday = 1
  return calendar.dateFromComponents(dateComponents)!
}

Upvotes: 1

Peter Lapisu
Peter Lapisu

Reputation: 21005

- (NSDate *)firstDateOfWeekWithDate:(NSDate *)date {

    NSCalendar * calendar = [NSCalendar currentCalendar];

    NSDateComponents *weekdayComponents = [calendar components:(NSDayCalendarUnit | NSWeekdayCalendarUnit) fromDate:date];

    NSDateComponents *components = [calendar components:(NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit | NSWeekdayCalendarUnit) fromDate:date];
    [components setDay:-((([weekdayComponents weekday] - [calendar firstWeekday]) + 5 ) % 7)];

    return [calendar dateFromComponents:components];
}

Upvotes: 2

Wolfgang
Wolfgang

Reputation: 4925

The solution by naixn will produce wrong results if monday (2) is set of the firstWeekday and the date you are inspecting is sunday. In this case you will get as a result the monday of next week.

The correct way would be to calculate the subtraction components as follows:

[componentsToSubtract setDay: - ((([weekdayComponents weekday] - [gregorian firstWeekday])
                                  + 7 ) % 7)];

Assuming that you always have 7 days in a week.

Upvotes: 12

Thibault Martin-Lagardette
Thibault Martin-Lagardette

Reputation: 4733

I think this threads responds to what you're looking for: http://www.cocoabuilder.com/archive/cocoa/211648-nsdatecomponents-question.html#211826

Note however that it doesn't handle Mondays as first days of the week, so you may have to tweek it a little by substracting [gregorian firstWeekday] instead of just 1. Also, I modified it to use -currentCalendar, but it's up to you :-)

NSDate *today = [NSDate date];
NSCalendar *gregorian = [NSCalendar currentCalendar];

// Get the weekday component of the current date
NSDateComponents *weekdayComponents = [gregorian components:NSWeekdayCalendarUnit fromDate:today];
/*
Create a date components to represent the number of days to subtract
from the current date.
The weekday value for Sunday in the Gregorian calendar is 1, so
subtract 1 from the number
of days to subtract from the date in question.  (If today's Sunday,
subtract 0 days.)
*/
NSDateComponents *componentsToSubtract = [[NSDateComponents alloc] init];
/* Substract [gregorian firstWeekday] to handle first day of the week being something else than Sunday */
[componentsToSubtract setDay: - ([weekdayComponents weekday] - [gregorian firstWeekday])];
NSDate *beginningOfWeek = [gregorian dateByAddingComponents:componentsToSubtract toDate:today options:0];

/*
Optional step:
beginningOfWeek now has the same hour, minute, and second as the
original date (today).
To normalize to midnight, extract the year, month, and day components
and create a new date from those components.
*/
NSDateComponents *components = [gregorian components: (NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit)
                                            fromDate: beginningOfWeek];
beginningOfWeek = [gregorian dateFromComponents: components];

Upvotes: 36

jtbandes
jtbandes

Reputation: 118781

Use NSDateComponents and set the weekday to 1.

Upvotes: 0

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