CODEWITHSUNDEEP
c++
greywolf82
greywolf82

Reputation: 22193

Overloaded method with template

I've got the following classes:

class A: public Util<double> {}

class B: public Util<double>, public Interface {}

template<class T>
class MyTmp {
public:
    void foo(const A& a);
}


class MyClass: public MyTmp<Other> {
public:
   void foo(const B& b);
}

When I call foo using an instance of MyClass with a A object for unknown reason the foo method of MyClass is called instead of foo of class MyTmp. I'm using gcc 4.4.2 using -O3. Any tips?

Upvotes: 3

Views: 61

Answers (1)

TartanLlama
TartanLlama

Reputation: 65770

Member functions in derived classes with the same names as those in base classes hide the functions in the base class.

If you want MyTmp<T>::foo to be available from MyClass, you could as a using-directive:

class MyClass: public MyTmp<Other> {
public:
   using MyTmp::foo;
   void foo(const B& b);
}

Upvotes: 7

Related Questions