CODEWITHSUNDEEP
c++compilationg++shared-libraries
jorgen
jorgen

Reputation: 3593

Compiling with c++ and getting "ready to go" executable

Is it possible to compile a program with g++ so that shared libraries etc are "included" with the executable?

I have a c++ program that I'd like to compile and run at another location where I'm missing some libraries and don't have install access.

The main reason I couldn't find answers for this is probably that I don't know how to call it..

Upvotes: 1

Views: 58

Answers (1)

Jonathan Wakely
Jonathan Wakely

Reputation: 171383

No, it's not possible.

Either link statically (with -static) so it doesn't use any shared libraries, or copy the shared libraries to the other location along with the executable.

Since the shared libraries will not be in the dynamic loader's usual search paths you'll need to ensure they can be found, either by setting the LD_LIBRARY_PATH environment variable when running the program, or by setting an RPATH in the executable when you build it.

(Assuming you're using the GNU linker ...) To set an RPATH in the executable link with '-Wl,-rpath,$ORIGIN' (the quotes are important, to stop $ORIGIN being expanded by the shell). That means the loader will look for shared libraries in the same directory as the executable itself.

See https://gcc.gnu.org/onlinedocs/libstdc++/faq.html#faq.how_to_set_paths and https://gcc.gnu.org/onlinedocs/libstdc++/manual/using_dynamic_or_shared.html#manual.intro.using.linkage.dynamic for more information.

Upvotes: 2

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