Reputation: 43
I've got a DAG of tasks that I'm trying to execute using the boost::shared_future
framework.
For example concreteness, consider the data flow graph shown in the figure.
Here's an attempt to code this up:
#include <iostream>
#define BOOST_THREAD_PROVIDES_FUTURE
#define BOOST_THREAD_PROVIDES_FUTURE_CONTINUATION
#define BOOST_THREAD_PROVIDES_FUTURE_WHEN_ALL_WHEN_ANY
#include <boost/thread/future.hpp>
using namespace boost;
int main() {
shared_future<int> fa = async([]() { sleep(1); return 123; });
shared_future<int> fb = async([]() { sleep(2); return 456; });
shared_future<int> fc = async([]() { sleep(5); return 789; });
auto fabc = when_all(fa,fb,fc);
auto fx = fabc.then([](decltype(fabc)) {
std::cout << "A,B,C has completed, computing X\n";
return 1;
});
auto fax = when_all(fa,std::move(fx));
auto fz = fax.then([](decltype(fax)) {
std::cout << "A,X has completed, computing Z\n";
return 2;
});
auto fcx = when_all(fc,std::move(fx)); // <---- BAD
auto fy = fcx.then([](decltype(fcx)) {
std::cout << "C,X has completed, computing Y\n";
return 3;
});
fy.get();
fz.get();
}
However, this doesn't work (obviously, since I'm calling std::move
twice on fx
). I guess the question is- is there a way to get when_all
and then
to return "shared" types so that this executes sensibly? Or is task-DAG execution beyond the limits of what boost can do?
Upvotes: 4
Views: 1144
Reputation: 393084
Like T.C. said, you can share your future by calling the share()
member function. That way you don't need to move twice:
#include <iostream>
#define BOOST_THREAD_PROVIDES_FUTURE
#define BOOST_THREAD_PROVIDES_FUTURE_CONTINUATION
#define BOOST_THREAD_PROVIDES_FUTURE_WHEN_ALL_WHEN_ANY
#include <boost/thread/future.hpp>
using namespace boost;
using boost::this_thread::sleep_for;
using boost::chrono::milliseconds;
int main() {
shared_future<int> fa = async([]() { sleep_for(milliseconds(100)); return 123; });
shared_future<int> fb = async([]() { sleep_for(milliseconds(200)); return 456; });
shared_future<int> fc = async([]() { sleep_for(milliseconds(500)); return 789; });
auto fabc = when_all(fa, fb, fc);
auto fx = fabc
.then([](decltype(fabc)) { std::cout << "A,B,C has completed, computing X\n"; return 1; })
.share();
auto fax = when_all(fa, fx);
auto fz = fax
.then([](decltype(fax)) { std::cout << "A,X has completed, computing Z\n"; return 2; })
.share();
auto fcx = when_all(fc, fx);
auto fy = fcx
.then([](decltype(fcx)) { std::cout << "C,X has completed, computing Y\n"; return 3; })
.share();
fy.get();
fz.get();
}
Prints
A,B,C has completed, computing X
C,X has completed, computing Y
A,X has completed, computing Z
Upvotes: 3