CODEWITHSUNDEEP
python
User
User

Reputation: 13

Elif error occured while the python programming

# Get the input values.
b1 = input('Please enter the base.')
i1 = input('Please enter the index.')

# Define the funciton with parameter 'base' and 'index'.
def square(base, index):
    if base == 0:
        print('Can\'t calculate because base is equal to 0.')
    elif (not base == 0) and index == 0:
        print('The value is 0, because base is greater than 1, and index is equal to 0.')
    elif (not base == 0) and index == 1:
        print('The answer is equal to base, because index is equal to 1. Therefore, The answer is {ans}.'.format(ans=base))
    elif (not base == 0) and index == 2:
        print('{b} squared is {c}.'.format(b=base, c=(b ** 2))
    elif (not base == 0) and (index > 2 or index < 0):
        print('{b} to the power of {i} is equal to {c}'.format(b=base, i=index, c=base**index))

# Print the function.
print(square(b1, i1))

The error is this:

line 36, elif (not base == 0) and (index > 2 or index < 0):

SyntaxError: invalid syntax

I use python 3.5.1. How can I fix this error?

Upvotes: 1

Views: 57

Answers (1)

zondo
zondo

Reputation: 20336

The problem is not on that line, but on the line above. You did not close enough parentheses. Try adding another close parenthesis to the end of the previous line.

Upvotes: 1

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