CODEWITHSUNDEEP
tfstfsbuildtfs-2015
Kemy
Kemy

Reputation: 266

TFS 2015 Build vNext recursive variable substitution

Is it possible that the variable substitution is not recursive?

Example1:

Variable Value

SqlInstance (localDb)\mssqllocaldb

DbCatalogName FooDb

ConnStr data source=$(SqlInstance);initial catalog=$(DbCatalogName)$(Build.BuildId);

During the build the connection string substituted to: data source=(localDb)\mssqllocaldb;initial catalog=FooDb3211;

This configuration works perfectly. But if i move the BuildId parameter to DbCatalogName variable it won't be substituted.

Example2:

Variable Value

SqlInstance (localDb)\mssqllocaldb

DbCatalogName FooDb$(Build.BuildId)

ConnStr data source=$(SqlInstance);initial catalog=$(DbCatalogName);

With this configuration the connection string is substituted to: data source=(localDb)\mssqllocaldb;initial catalog=FooDb$(Build.BuildId);

So how can i chain variables with vNext?

Upvotes: 1

Views: 589

Answers (2)

Kemy
Kemy

Reputation: 266

Variable chaining seems to work with TFS 2015 Update 3.

Upvotes: 0

Eddie Chen - MSFT
Eddie Chen - MSFT

Reputation: 29976

If you want the "DbCatalogName" variable contain the BuildID value, I recommend you to add an additional power-shell build step to set the value of "DbCatalogName".

The code to set a variable value:

##vso[task.setvariable variable=testvar;]testvalue

Upvotes: 0

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