Reputation: 1
This is a simple begginer program with setter and getter concept now i have to make it to first enter user name and password to get welcomed and IF I ENTER WRONG INFO IT SHOULD DISPLAY INVALID AND 5 TRIES LEFT THEN if i again enter wrong info it should display 4 tries left and so on and finally when all tries are over it should hang the program or lock the screen or so
using System;
namespace ConsoleApplication4
{
class Program
{
static void Main(string[] args)
{
demo obj = new demo();
string uname, pass;
Console.ForegroundColor = ConsoleColor.Green;
label1:
Console.Clear();
Console.WriteLine("Enter username");
uname = Console.ReadLine();
Console.WriteLine("Enter Password");
pass = Console.ReadLine();
obj.setName(uname);
obj.setPass(pass);
if (obj.getName() == "niit")
{
if (obj.getPass() == "1234")
{
Console.WriteLine("welcome");
}
}
else
{
Console.Clear();
Console.WriteLine("Invalid");
Console.WriteLine("\n \n \n To try again enter y");
int n = 5;
string yes = Console.ReadLine();
if (yes == "y")
{
while (n >= 1)
{
Console.Write(n + " Tries left");
goto label1;
n = --n;
}
}
}
Console.ReadKey();
}
}
class demo
{
private string name, pass;
public void setName(string name)
{
this.name = name;
}
public string getName()
{
return name;
}
public void setPass(string pass)
{
this.pass = pass;
}
public string getPass()
{
return pass;
}
}
}
Please suggest a simple begginers code to make the loop work and make the count down
Upvotes: 0
Views: 370
Reputation:
namespace ConsoleApplication4
{
class Program
{
static void Main(string[] args)
{
demo obj = new demo();
string uname, pass;
boolean successful = false;
int32 tries = 5;
Console.ForegroundColor = ConsoleColor.Green;
label1:
Do
{
Console.Clear();
Console.WriteLine("Enter username");
uname = Console.ReadLine();
Console.WriteLine("Enter Password");
pass = Console.ReadLine();
obj.setName(uname);
obj.setPass(pass);
if (obj.getName() == "niit")
{
if (obj.getPass() == "1234")
{
Console.WriteLine("welcome");
successful = true;
}
}
if (!successful)
{
tries--;
Console.Clear();
Console.WriteLine("Invalid");
if (tries > 1)
{
Console.WriteLine("Have " + tries + " attempts left");
}
ElseIf (tries == 1)
{
Console.WriteLine("Have only one more attempt left");
}
Else
{
Console.WriteLine("Maximum number of tries exceed");
Console.WriteLine("Goodbye");
}
}
} While(!successful && Tries > 0);
}
}
Upvotes: 0
Reputation: 1130
you problems are the following nested if
-contitions
if (obj.getName() == "niit")
{
if (obj.getPass() == "1234")
{
Console.WriteLine("welcome");
}
}
else
{
\\...
}
If the username is correct and the pass not, it wont enter the else branch.
a better solution to ask for input until it is valid id a do ... while
loop
Following example has a lot of improvements over yours.
static void Main(string[] args)
{
demo obj = new demo();
string uname, pass;
Console.ForegroundColor = ConsoleColor.Green;
int maxTries;
int tries = maxTries = 5;
do
{
if (tries != maxTries)//second and more
{
Console.Clear();
Console.WriteLine("Invalid");
Console.Write("\n\t" + tries + " Tries left");
Console.WriteLine("\n\n\n\tTry again? (y/n)");
string input;
do
{
input = Console.ReadLine();
} while (input != "y" && input != "n");
if (input == "n")
{
return; // exit the program
}
}
Console.Clear();
Console.WriteLine("Enter username");
uname = Console.ReadLine();
Console.WriteLine("Enter Password");
pass = Console.ReadLine();
obj.setName(uname);
obj.setPass(pass);
tries--;
} while (obj.getName() != "niit" || obj.getPass() != "1234");
Console.WriteLine("Wellcome");
}
PS: Classes should start with a capital letter.
goto
is a relict of old times, it will mess with your programm structure and make things more complicated than they are. The only propper use i know is for fallthrough in switches, which also is needed only in rare cases.
A madeup one would be:
string vehicleType = "car";
switch(vehicleType)
{
case "truck":
Console.WriteLine("two wheeles and");
goto case "car";
case "car":
Console.WriteLine("two wheeles and");
goto case "motor cycle";
case "motor cycle":
Console.WriteLine("two wheeles");
break;
case "boat":
Console.WriteLine("no wheeles");
break;
}
Upvotes: 0
Reputation: 38
try this updated main method:
static void Main(string[] args)
{
demo obj = new demo();
int n = 5;
string uname, pass;
Console.ForegroundColor = ConsoleColor.Green;
//Console.Clear();
label1:
Console.WriteLine("\n");
Console.WriteLine("Enter username");
uname = Console.ReadLine();
Console.WriteLine("Enter Password");
pass = Console.ReadLine();
obj.setName(uname);
obj.setPass(pass);
if (obj.getName() == "niit" && obj.getPass() == "1234")
{
Console.WriteLine("welcome");
}
else
{
//Console.Clear();
if (n < 1)
{
//Add ur screenlock n hang prog code
Console.Clear();
Console.WriteLine("ScreenLock");
}
else
{
Console.WriteLine("\n Invalid");
Console.WriteLine("\n To try again enter y");
string yes = Console.ReadLine();
Console.WriteLine("\n");
if (yes == "y")
{
while (n >= 1)
{
Console.Write(n + " Tries left");
n = --n;
goto label1;
}
}
}
}
Console.ReadKey();
}
Upvotes: 0
Reputation: 1825
A while loop should suffice. Using a boolean to detect successful password entry. When entered, it will break out of the loop. invalid attempts will decrement the AttemptsLeft int. Note: I haven't tried this in Visual Studio, the logic should be sound, but I recommend debugging and stepping through it to test if it meets your criteria.
static void Main(string[] args)
{
demo obj = new demo();
string uname, pass;
Console.ForegroundColor = ConsoleColor.Green;
label1:
Console.Clear();
Console.WriteLine("Enter username");
uname = Console.ReadLine();
Console.WriteLine("Enter Password");
bool SuccessfulPassword = false;
int AttemptsLeft = 5;
while(!SuccessfulPassword && AttemptsLeft > 0){
pass = Console.ReadLine();
obj.setName(uname);
obj.setPass(pass);
if (obj.getName() == "niit")
{
if (obj.getPass() == "1234")
{
Console.WriteLine("welcome");
SuccessfulPassword = true;
}
}
else
{
AttemptsLeft--;
Console.Clear();
Console.WriteLine("Invalid");
Console.WriteLine("\n \n \n To try again enter y");
int n = 5;
string yes = Console.ReadLine();
if (yes == "y")
{
Console.Write(AttemptsLeft + " Tries left");
}
}
Console.ReadKey();
}
}
Upvotes: 3
Reputation: 11
Everytime you get the wrong input, you remaking your count int n = 5;
so everytime you have 5 tries left.
What you can do is to declare your count outside of the static void Main(string args[])
method
just like:
int n =5;
static void Main(string args[])
{
}
Upvotes: 0