usert4jju7
usert4jju7

Reputation: 1813

PHP - Exact match string in a sentence

I have the following function to do a "exact match" of a pattern($searchPat) in a sentence ($sourceStr)

function isUsed($sourceStr, $searchPat) {
 if (strpos($sourceStr, $searchPat) !== false) {
    return true;
    } else {
    return false;
    }
}

However, this doesn't do an exact match. I changed the function as follows but this doesn't even execute.

function isUsed($sourceStr, $searchPat) {
if (preg_match("~\b[$sourceStr]\b~", $searchPat)) {
    return true;
    } else {
    return false;
    }
}

How could I do an exact match please?

Upvotes: 2

Views: 7548

Answers (4)

Sahil Gulati
Sahil Gulati

Reputation: 15141

You can try this one:

  function isUsed($string_to_search, $source_String) {
    if (preg_match("/$string_to_search/", $source_String)) {
    return true;
    } else {
     return false;
    }
 }

You can change according to your need.

Case insensitive: preg_match("/$string_to_search/i", $source_String)
Boundry condition: preg_match("/\b$string_to_search\b/i", $source_String)
Special characters: if you have any special characters in your string for your safe side replace it with '\special_character'

Upvotes: 0

chris85
chris85

Reputation: 23892

The [] is a character class. That lists characters you want to allow, for example [aeiou] would allow a vowel. Your variables are also in the inverted order, pattern first, then string to match against. Try this:

function isUsed($sourceStr, $searchPat) {
     if (preg_match("~\b$searchPat\b~", $sourceStr)) {
         return true;
     } else {
         return false;
     }
}

Additional notes, this is case sensitive, so Be won't match be. If the values you are passing in are going to have special characters the preg_quote function should be used, preg_quote($variable, '~'). You also may want to concatenate the variable so it is clear that that is a variable and not part of the regex. The $ in regex means the end of the string.

Upvotes: 5

Jalpa
Jalpa

Reputation: 720

Please try "preg_match" for matches.

$string = 'test';
if ( preg_match("~\btest\b~",$string) )
  echo "matched";
else
  echo "no match";

Or try like this

if(stripos($text,$word) !== false) 
      echo "no match";
    else
      echo "match";

Upvotes: 0

Ahmed Abu Taha
Ahmed Abu Taha

Reputation: 91

Try This.

function isUsed($sourceStr, $searchPat) {
if (preg_match("/\b".preg_quote($sourceStr)."\b/i", $searchPat)) {
    return true;
    } else {
    return false;
    }
}

Upvotes: 2

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