nabulke
nabulke

Reputation: 11255

template specialization according to sizeof type

I would like to provide a templated function, that varies its implementation (->specialization) according to the sizeof the template type.

Something similar to this (omitted typecasts), but without the if/elseif:

template<class T>
T byteswap(T & swapIt)
{
    if(sizeof(T) == 2)
    {
        return _byteswap_ushort (swapIt);
    }
    else if(sizeof(T) == 4)
    {
        return _byteswap_ulong(swapIt);
    }
    else if(sizeof(T) == 8)
    {
        return _byteswap_uint64(swapIt);
    }
            throw std::exception();
}

I know there are many roads to reach my goal, but since I try to learn about SFINAE and type traits I'm particularly interested in solutions using those techniques to decide at compile time which specialization to choose and which calls are not admitted.

Perhaps implementing a class trait is_4ByteLong and using boost::enable_if...

I have to admit, I'm stuck right now, so I thank you for any help or advice

Upvotes: 21

Views: 10592

Answers (4)

valdo
valdo

Reputation: 12933

I can propose the following method: Its benefit is that you don't have to throw an exception if the operand isn't of the valid size. It just won't link. So that you have the error checking at build time.

template<int size>
void byteswapInPlace(void* p);

template<> void byteswapInPlace<1>(void* p) { /* do nothing */ }

template<> void byteswapInPlace<2>(void* p)
{
    _byteswap_ushort((ushort*) p);
}

template<> void byteswapInPlace<4>(void* p)
{
    _byteswap_ulong((ulong*) p);
}

template<> void byteswapInPlace<8>(void* p)
{
    _byteswap_uint64((uint64*) p);
}


template<class T>
T byteswap(T & swapIt)
{
    byteswapInPlace<sizeof(T)>(&swapIt);
    return swapIt;
}

Upvotes: 1

Matthieu M.
Matthieu M.

Reputation: 299760

Just for the sake of demonstrating enable_if in action, since you spoke about it:

template <class T>
typename boost::enable_if_c< sizeof(T) == 2, T >::type
swapIt(T& rhs) { return _byteswap_short(rhs); }

template <class T>
typename boost::enable_if_c< sizeof(T) == 4, T >::type
swapIt(T& rhs) { return _byteswap_long(rhs); }

etc...

And of course, instead of throwing, there is just no implementation if the type doesn't meet any of the requirement and thus you have a compile time error.

Two notes:

  • Use of typename and ::type are mandatory
  • I used enable_if_c because my expression evaluates to a boolean value directly, whereas enable_if requires a type containing a ::value member which is a boolean.

Upvotes: 3

kennytm
kennytm

Reputation: 523214

You don't need SFINAE or type traits. Vanilla template specialization is enough. Of course it must be specialized on structs as C++(98) doesn't support function template partial specialization.

template <typename T, size_t n>
struct ByteswapImpl
/*
{
  T operator()(T& swapIt) const { throw std::exception(); }
}
*/    // remove the comments if you need run-time error instead of compile-time error.
;

template <typename T>
struct ByteswapImpl<T, 2> {
  T operator()(T& swapIt) const { return _byteswap_ushort (swapIt); }
};

// ...

template <typename T>
T byteswap(T& swapIt) { return ByteswapImpl<T, sizeof(T)>()(swapIt); }

Upvotes: 20

Philipp
Philipp

Reputation: 49802

Simply make an auxiliary class that takes the size as a template argument:

#include <cstddef>
#include <iostream>


template<std::size_t Size>
struct ByteSwapper { };

template<>
struct ByteSwapper<2> {
  static unsigned short swap(unsigned short a) {
    return 2 * a;
  }
};

template<typename T>
T byteswap(const T& a) {
  return ByteSwapper<sizeof(T)>::swap(a);
}


int main() {
  unsigned short s = 5;
  std::cout << byteswap(s) << std::endl;
  unsigned int i = 7;
  // std::cout << byteswap(i) << std::endl; // error
}

Upvotes: 4

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