Reputation: 31
How would i build an algorithm here in the most efficient way possible to find minimum value from list? I know the list hasnt done in the best way but, any ideas how to do ? I have tried few ways but dont seem to get it work efficiently..
Thanks.
class MainClass
{
public class List
{
public int maxSize = 50;
public int MaxSize
{
get
{
return maxSize;
}
set
{
maxSize = value;
}
}
public int firstEmpty = 0;
public int FirstEmpty
{
get
{
return firstEmpty;
}
set
{
firstEmpty = value;
}
}
public int[] data;
public List()
{
data = new int[maxSize];
}
public int returnValueAtIndex(int i)
{
return data[i];
}
public void setValueAtIndex(int v, int i)
{
data[i] = v;
}
}
public static int FIRST(List L)
{
if (END(L) > 0)
return 0;
else
return -1;
}
public static int END(List L)
{
return L.FirstEmpty;
}
public static int NEXT(int p, List L)
{
if (p >= 0 && p < L.MaxSize && p < END(L))
return p+1;
else
return - 1;
}
public static int PREVIOUS(int p, List L)
{
if (p >= 0 && p < L.MaxSize && p <= END(L))
return p-1;
else
return -1;
}
public static int LOCATE (int x, List L)
{
int i = 0;
while (i<END(L) && RETRIEVE(i, L) != x)
{
i++;
}
if (i != END(L))
return i;
else
return -1;
}
public static int RETRIEVE(int p, List L)
{
if (p >= 0 && p < END(L))
return L.returnValueAtIndex(p);
else
return -1;
}
public static void INSERT(int x, int p, List L)
{
if (p >= 0 && p < L.MaxSize && p <= END(L))
{
if (p == END(L))
{
L.setValueAtIndex(x, p);
}
else
{
for (int i = END(L); i > p; i--)
{
L.setValueAtIndex(L.returnValueAtIndex(i - 1), i);
L.setValueAtIndex(x, p);
}
}
L.FirstEmpty = END(L) + 1;
}
else
Console.WriteLine("Alkiota ei voitu lisätä");
}
public void DELETE(int p, List L)
{
if (p >= 0 && p < END(L))
{
for (int i = p; i < p - 1; i++)
{
L.setValueAtIndex(L.returnValueAtIndex(i + 1), i);
}
L.FirstEmpty = END(L) - 1;
}
}
public void MAKENULL(List L)
{
L.FirstEmpty = 0;
}
public static void PRINT(List L)
{
Console.WriteLine("Listan sisältö:");
for (int i = 0; i < END(L); i++)
{
Console.Write(L.returnValueAtIndex(i) + " ");
}
Console.WriteLine();
}
public static void Main(string[] args)
{
List testilista = new List();
INSERT(2, END(testilista), testilista);
INSERT(7, END(testilista), testilista);
INSERT(9, END(testilista), testilista);
INSERT(12, END(testilista), testilista);
INSERT(9, END(testilista), testilista);
INSERT(38, END(testilista), testilista);
Console.WriteLine("testilista");
PRINT(testilista);
Console.ReadLine();
}
}
}
Upvotes: 1
Views: 6752
Reputation: 518
The easiest way to do that in C# is with LinQ:
var minValue = data.Min();
if you want the highest value:
var maxValue = data.Max();
Upvotes: 4
Reputation: 92
I don't think this is the best option. For me there is two ways.
Sort your list by this code.
int valueMin = L.returnValueAtIndex(0);
for (int i = 0; i < END(L); i++)
{
//if the value of i is smaller than the value
if (valueMin < L.returnValueAtIndex(i))
{
//i become the min Value
valueMin = L.returnValueAtIndex(i);
}
}
Console.WriteLine(valueMin);
Console.Read();
Or in C# you can use Array.Sort
Array.Sort(L);
Console.WriteLine(L.returnValueAtIndex(0));
Console.Read();
I hope this will help you !
Upvotes: 0
Reputation: 1877
Note: Answer is not specific to C#
Given an unordered list of numbers, the fastest way to find the smallest number in the list is to look at every element in the list.
var unorderedList = [5,4,3,2,6,7,-23,8,-64,2,0,6];
function findSmallest(anArray){
var lowest = anArray[0];
for(var i = 1; i < anArray.length; i++){
var num = anArray[i];
if(num < lowest){
lowest = num;
}
}
return lowest;
}
var smallest = findSmallest(unorderedList);
console.log(smallest); //prints -64
You can run the code here
hit the run button
Upvotes: 2