CODEWITHSUNDEEP
pythonpython-2.7python-2.x
A.raven
A.raven

Reputation: 105

Count how many times each letter appears in a text sample

I need a function that counts how many times each individual letter appears in a string. It has to count capitals and lowercase as the same letter. I sort of did it, but its not exactly pretty.

def lmao(x):

    aye=x.count("a")
    Aye=x.count("A")
    bye=x.count("b")
    Bye=x.count("B")
    cye=x.count("c")
    Cye=x.count("C")
    dye=x.count("d")
    Dye=x.count("D")
    Eye=x.count("E")
    eye=x.count("e")
    Fye=x.count("F")
    fye=x.count("f")
    Gye=x.count("G")
    gye=x.count("g")
    Hye=x.count("H")
    hye=x.count("h")
    Iye=x.count("I")
    iye=x.count("i")
    Jye=x.count("J")
    jye=x.count("j")
    Kye=x.count("K")
    kye=x.count("k")
    Lye=x.count("L")
    lye=x.count("l")
    Mye=x.count("M")
    mye=x.count("m")
    Nye=x.count("N")
    nye=x.count("n")
    Oye=x.count("O")
    oye=x.count("o")
    Pye=x.count("P")
    pye=x.count("P")
    Qye=x.count("Q")
    qye=x.count("q")
    rye=x.count("r")
    Rye=x.count("R")
    sye=x.count("s")
    Sye=x.count("S")
    tye=x.count("t")
    Tye=x.count("T")
    uye=x.count("u")
    Uye=x.count("U")
    Vye=x.count("V")
    vye=x.count("v")
    Wye=x.count("W")
    wye=x.count("w")
    Xye=x.count("X")
    xye=x.count("x")
    Yye=x.count("Y")
    yye=x.count("y")
    Zye=x.count("Z")
    zye=x.count("z")
    killme=(aye+Aye,bye+Bye,cye+Cye,Dye+dye,Eye+eye,Fye+fye,Gye+gye,Hye+hye,Iye+iye,jye+Jye,Kye+kye,Lye+lye,Mye+mye,Nye+nye,Oye+oye,Pye+pye,Qye+qye,rye+Rye,sye+Sye,Tye+tye,uye+Uye,Vye+vye,Wye+wye,xye+Xye,Yye+yye,Zye+zye)
    return killme

So yeah, thats the disaster that I came up with. Is there any way to shorten this process?

Upvotes: 2

Views: 3075

Answers (4)

Alexander
Alexander

Reputation: 109736

Use counter together with a dictionary comprehension to get the count of each letter.

import string
from collections import Counter

For an alpha sorted tuple,

def count_letter_tuples(sentence):
    return tuple(Counter(sentence.lower()).get(c, 0) for c in string.ascii_lowercase)

>>> count_letter_tuples("Some Big Sentence")
(0, 0, 1, 0, 4, 0, 1, 0, 1, 0, 0, 0, 1, 2, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0)

Or for a dictionary response:

def count_letters(sentence):
    return {c: Counter(sentence.lower()).get(c, 0) for c in string.ascii_lowercase}

>>> count_letters("Some Big Sentence")
{'a': 0,
 'b': 1,
 'c': 1,
 'd': 0,
 'e': 4,
 'f': 0,
 'g': 1,
 'h': 0,
 'i': 1,
 'j': 0,
 'k': 0,
 'l': 0,
 'm': 1,
 'n': 2,
 'o': 1,
 'p': 0,
 'q': 0,
 'r': 0,
 's': 2,
 't': 1,
 'u': 0,
 'v': 0,
 'w': 0,
 'x': 0,
 'y': 0,
 'z': 0}

Upvotes: 0

Zubair Azami
Zubair Azami

Reputation: 65

This may help:

def counter(text):
    count_list = []
    for char in "abcdefghijklmnopqrstuvwxyz":
        count_list.append(text.lower().count(char))
    return tuple(count_list)

print(counter("Helllo123"))

Output:

(0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 3, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0)

Upvotes: 0

Brian
Brian

Reputation: 2242

To return exactly what you've requested:

import string
def lmao(x):
    return tuple(x.lower().count(c) for c in string.lowercase)

Upvotes: 2

limasxgoesto0
limasxgoesto0

Reputation: 4793

Use collections.Counter https://docs.python.org/2/library/collections.html#counter-objects

from collections import Counter    
counter = Counter(mystr.lower())

will give you all occurrences of each letter, ignoring case

Upvotes: 5

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