CODEWITHSUNDEEP
java
Matt
Matt

Reputation: 21

replacing system.out.println(class) in java

I've got some classes which include toString functions which work very well as:

snipped of declaration:

public String toString() {
        return "Port info: "+myPort.variable;
    }

snipped of main():

Port myPort;
myPort.fillInfo();
system.out.println(myPort);

output:

"Port info: 123"

I'm trying to replace all my system.out.println(myPort) calls with myWindow.println(myPort) calls where myWindow contains:

public void println(String toPrint)
{
    textArea.append(toPrint+"\n"); //or insert
}

However, I'm getting:

The method println(String) in the type window is not applicable for the arguments (Port)

In other words, my declaration is expecting the String type, and I'm trying to pass it the Port type.

Somehow, system.out.println() will take any class that's got a toString() declared.

How does system.out.println take any class and print it out, and run its toString() method if it exists? And, more to the point, how can I replicate this functionality for my own println() function?

Upvotes: 2

Views: 3147

Answers (4)

Elliott Frisch
Elliott Frisch

Reputation: 201439

First, please don't use \n as a line separator (it isn't portable). In addition to overloading println(Object), you could make your method generic. Something like

public <T> void println(T obj)
{
    textArea.append(String.format("%s%n", obj)); 
}

or

public void println(Object obj)
{
    textArea.append(String.format("%s%n", obj)); 
}

or

public void println(Object obj)
{
    textArea.append((obj == null ? "null" : obj.toString()) 
            + System.lineSeparator()); 
}

Upvotes: 2

Orlando
Orlando

Reputation: 1

The problem is that System.out has a method to print to console an object as it contains for all primitive data types. The thing about this is that as all methods have the same name and just change the data type of the parameter you want to print, you think you can pass an object by a string and is not. The method .println() automatically takes which passes an object. Within this method .println() he takes the object that you indicated by parameters and calls his method .toString() to obtain the string representation of the object and printed on the console.

If you want to print any type of object you must declare your parameter as object type and invoke the method .toString() from the object and print that information.

Upvotes: 0

Scary Wombat
Scary Wombat

Reputation: 44834

Change your Window to

public void println(Object obj)
{
    textArea.append(obj +"\n"); 
}

Upvotes: 3

C. K. Young
C. K. Young

Reputation: 223003

PrintStream.println has an overload that takes an Object argument. You can make your println do the same.

Upvotes: 2

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