CODEWITHSUNDEEP
pythonruntime-error
Bernardo OS
Bernardo OS

Reputation: 331

UVa Run time error in Python

So I'm trying to solve the following problem from the UVa online judge: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2864

I've written the following code in Python:

t = int(input())
for i in range(t):
    highs = 0
    lows = 0
    walls = int(input())
    heights = [0]*50
    for h in range(walls):
        heights[h] = (int(input()))
    for j in range(1, walls):
        if (heights[j] < heights[j - 1]):
            highs += 1
        elif (heights[j] > heights[j - 1]):
            lows += 1
    print("Case %d: %d %d" % (i + 1, highs, lows))

exit(0)

Every time I try my code with different test cases I get the expected output; it works perfectly fine in my side but when I submit it I keep on getting a Runtime Error. I'm desperate now as I have tried a million things and nothing works. Please, help.

Upvotes: 0

Views: 2368

Answers (2)

melalonso
melalonso

Reputation: 228

As suggested the Runtime Error is in this part of your code:

for h in range(walls):
    heights[h] = (int(input()))

that you can change for 

heights = [int(i) for i in input().split()]

and omit the line

heights = [0]*50

Another thing that I found is that you are counting in a contrary manner lows and highs. You should do:

    if (heights[j] < heights[j - 1]):
        lows += 1
    elif (heights[j] > heights[j - 1]):
        highs += 1

That should work. Hope you get the solution Accepted ;)

Upvotes: 0

Hugh Bothwell
Hugh Bothwell

Reputation: 56694

I think the error is here:

for h in range(walls):
    heights[h] = (int(input()))

input() reads a line, thenint() tries to convert the line to an integer. But "1 4 2 2 3 5 3 4" cannot be converted to an integer, and if you read 8 lines you will probably run out of input.

Instead, try

heights = [int(i) for i in input().split()]

which should return [1, 4, 2, 2, 3, 5, 3, 4].

Upvotes: 1

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