CODEWITHSUNDEEP
phpooplaravel-5
sajad Ayooby
sajad Ayooby

Reputation: 140

Using Interface without using argument in function on laravel

i developing a laravel 5 package and now i want to use: interface Gate, on laravel.

in order to use interfaces, i should do by this way:

     public function boot(GateContract $gate)
      {
...code...

$gate->define($permission->name)

    ...Codes...
       }

but i want to know is there another way use GateContract $gate without using argument of function or with using extend from class.

i mean, can i use like this way:

$gate = new Gate;

or any thing else,

Upvotes: 1

Views: 88

Answers (1)

Margus Pala
Margus Pala

Reputation: 8673

Try something like that

$gate = $this->app->make('Gate');

There is more information about the Laravel Service container which instantiates objects over here https://laravel.com/docs/5.2/container

Upvotes: 1

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