CODEWITHSUNDEEP
julia
Lanting Guo
Lanting Guo

Reputation: 805

The principle of binary representation of data types in Julia

julia> type TestA
       a::Int32
       b::Int64
       end
julia> type TestB
       a::Int64
       b::Int64
       end

julia> sizeof(TestA),sizeof(TestB)
(16,16)

I am expeced that sizeof(TestA) will be 4+8=12.

I am curious about the principle behind the scenes.

Why TestA and TestB have the same size?

ps: http://docs.julialang.org/en/latest/devdocs/object/ is a good material

Upvotes: 3

Views: 519

Answers (1)

David Hoelzer
David Hoelzer

Reputation: 16331

Byte alignment is the answer. The documentation states that:

Note that all objects are allocated in multiples of 4 bytes and aligned to the platform pointer size.

Upvotes: 8

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