Reputation: 5463
How to manipulate the date and exclude saturday and sunday?. The objective is, I need to create a cron job that will run and execute on datas that were created 5 days ago,"BUT", saturday and sunday shouldn't be included in that 5 days period.
here's what I have so far
$numdays = 5;
$today = strtotime('now');
$start = date('Y-m-d',strtotime('-'.$numdays.' day',$today));
echo $start;
if you try to run my code snippet above, it will show you the exact date 5 days ago 2016-02-10
. But that one doesn't "exclude" saturday and sunday in the computation. it should be be 2016-02-08
. So how to do that?
Upvotes: 2
Views: 75
Reputation: 2167
You can get a whole week and discard the weekends, keeping the furthest element in the array as a result.
$days = array_filter(array_map(function ($daysBack) {
$date = new \DateTimeImmutable("$daysBack days ago", new \DateTimeZone('UTC'));
return (!in_array($date->format('N'), [6, 7])) ? $date : null;
}, Range(1, 7)));
$fiveWorkingDaysAgo = end($days);
Upvotes: -1
Reputation: 2707
You can use PHP's date week of day, there are several versions, here is one using N
:
<?php
$current = new DateTime();
$interval = new DateInterval('P1D');
$x = 5;
while ($x > 1) {
// Check if day of week is not saturday/sunday (1 => Monday ... 7 -> Sunday)
if ($current->format('N') >= 6) {
$x++;
}
$current->sub($interval);
$x--;
}
echo $current->format('Y-m-d') . PHP_EOL;
Example Run.
Upvotes: 3