CODEWITHSUNDEEP
java
rcv40
rcv40

Reputation: 37

Java - How to read multiple values from the same line

I'm working on a java assignment and was stuck on this part. Basically we are to get the user to input three positive non-zero integers using the scanner.

It's supposed to look something like this

Enter three integer values: 2 2 10

The numbers (2, 2, 10) cannot form a triangle.

I was wondering how can I code it so that entering the "2 2 10" could be read as three different integers that are separated by a comma. Thank you very much in advance.

Upvotes: 1

Views: 5473

Answers (4)

i3rd
i3rd

Reputation: 66

You can make it as follows:

String sentence = scanner.nextLine();

And you can make:

String[] splittedByComma = sentence.split(",");

Or by space:

String[] splittedBySpace = sentence.split(" ");

Or an array list like the following example:

How to split a comma-separated string?

Then parse each of them to integers.

Upvotes: 0

pp_
pp_

Reputation: 3489

Read the input with java.util.Scanner and a for loop:

Scanner sc = new Scanner(System.in);
int[] values = new int[3];

for (int i = 0; sc.hasNextInt() && i < 3; i++) {
    values[i] = sc.nextInt();
}

Upvotes: 1

ya_pulser
ya_pulser

Reputation: 2670

scanner.nextInt is your answer

final BufferedReader input = new BufferedReader(
    new InputStreamReader(System.in));

// enter yours 2 2 10 and press Enter
final String line = input.readLine();

final Scanner s = new Scanner(line);
int a = s.nextInt(); // reads 2
int b = s.nextInt(); // reads 2
int c = s.nextInt(); // reads 10

if (a + b > c || a + c > b || b + c > a ) {
    System.out.println(
        "No triangle can be composed from " + a + ", " + b + ", " + c );
}

Upvotes: 0

T. Carsello
T. Carsello

Reputation: 39

Try this:

Scanner scan = new Scanner(System.in);
String line = scan.nextLine();
String[] inValues = line.split(" ");
int[] values = new int[inValues.length];
for(int i = 0; i < inValues.length; i++){
    values[i] = Integer.parseInt(inValues[i]);
}

Upvotes: 0

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