Reputation: 427
I want to show loading progress via a modal QDialog
. So I create a thread to load the data and call exec()
on the dialog.
loading_progress_dialog = LoadingProgressDialog(len(filenames))
loadingWorker = analyzer.LoadingWorker(filenames, loading_progress_dialog.apply_progress)
workingThread = QThread()
workingThread.started.connect(loadingWorker.process)
loadingWorker.finished.connect(workingThread.quit)
workingThread.finished.connect(loading_progress_dialog.accept)
loadingWorker.moveToThread(workingThread)
workingThread.start()
loading_progress_dialog.exec()
I want the dialog to be responsible but it freezes and I'm not able to move it around on the screen while the loading thread is running.
class LoadingProgressDialog(QLoadingProgressDialog, Ui_LoadingDialog):
def __init__(self, maxFiles):
super(LoadingProgressDialog, self).__init__()
self.setupUi(self)
self.progressBar.setMaximum(maxFiles)
self.setWindowTitle('Loading files...')
def apply_progress(self, delta_progress):
self.progressBar.setValue(delta_progress + self.progressBar.value())
class LoadingWorker(QtCore.QObject):
def __init__(self, file_names, progress_made):
super(LoadingWorker, self).__init__()
self._file_names = file_names
self._progress_made = progress_made
finished = QtCore.pyqtSignal()
def process(self):
print("Thread started")
# load_csv_data(self._file_names, self._progress_made)
QtCore.QThread.sleep(5)
self.finished.emit()
Am I fighting with GIL or is it another problem? And second thing I am worried about is race-condition between self.finished.emit()
and loading_progress_dialog.exec()
. If the working thread is finished faster than gui thread runs exec()
, the dialog will not close. Is there any way to ensure that everything is in right order?
Upvotes: 2
Views: 1596
Reputation: 2160
Your GUI freezes because it executes in the same thread as your worker - in main thread! How is this possible if you moved worker to different thread? Well, let's take a look at what exactly you've done:
# This connects signal to the instance of worker located in main thread
workingThread.started.connect(loadingWorker.process)
# Creates a copy of worker in the different thread
loadingWorker.moveToThread(workingThread)
# Signal reaches the instance of worker it was connected to -
# the instance belonging to main thread!
workingThread.start()
The fix is straightforward: move worker before attaching signals to it.
Race-condition is impossible if it is guaranteed that progress dialog receives command to show before closing one:
class LoadingWorker(QtCore.QObject):
[...]
def process(self):
self.ready.emit()
[...]
self.finished.emit()
loadingWorker.ready.connect(loading_progress_dialog.exec)
loadingWorker.finished.connect(loading_progress_dialog.close)
So, the simple program which updates UI by the order of the different thread may look like this:
from PyQt4 import QtGui, QtCore
from PyQt4.QtCore import QThread
from time import sleep
class LoadingProgressDialog(QtGui.QDialog):
def __init__(self):
super().__init__()
self.setWindowTitle('Loading files...')
def show_progress(self, p):
self.setWindowTitle('Loading files... {}%'.format(p))
class LoadingWorker(QtCore.QObject):
finished = QtCore.pyqtSignal()
ready = QtCore.pyqtSignal()
report_progress = QtCore.pyqtSignal(object)
def process(self):
print('Worker thread ID: %s' % int(QThread.currentThreadId()))
print("Worker started")
self.ready.emit()
for p in range(0, 100, 10):
self.report_progress.emit(p)
sleep(0.2)
print("Worker terminates...")
self.finished.emit()
if __name__ == '__main__':
import sys
app = QtGui.QApplication([])
print('Main thread ID: %s' % int(QThread.currentThreadId()))
workingThread = QThread()
loadingWorker = LoadingWorker()
loading_progress_dialog = LoadingProgressDialog()
loadingWorker.ready.connect(loading_progress_dialog.exec)
loadingWorker.report_progress.connect(loading_progress_dialog.show_progress)
loadingWorker.finished.connect(workingThread.quit)
loadingWorker.finished.connect(loading_progress_dialog.close)
loadingWorker.moveToThread(workingThread)
workingThread.started.connect(loadingWorker.process)
workingThread.start()
sys.exit(app.exec_())
Upvotes: 3