CODEWITHSUNDEEP
seleniumselenium-webdriverwebdriver
Vimal Raj
Vimal Raj

Reputation: 21

XPATH identifier from HTML

<ul class="popupmenu is-open" id="menuFormDefaultFC" role="menu" aria-hidden="false">
<li role="presentation"><a tabindex="-1" role="menuitem" href="#A">Add</a>

Please somebody let me know the Xpath for above html with href in it.

Upvotes: 0

Views: 138

Answers (4)

yojna
yojna

Reputation: 513

Use Firefox plugin "Firepath" to extract xpath.

https://addons.mozilla.org/en-US/firefox/addon/firepath/

Upvotes: 0

nilesh
nilesh

Reputation: 14289

Here are a few options for href.

1. By.xpath(".//a[@href='#A']");
2. By.xpath(".//li[@role='presentation']/a[@href='#A']");

But for links you could use just linkText. I prefer below for simplicity unless your app supports multiple locales.

By.linkText("Add");

Or use CSS selectors

1. By.cssSelector("a[role='presentation']");
2. By.cssSelector("li[role='presentation']>a[href='#A']");

Upvotes: 1

djangofan
djangofan

Reputation: 29669

I would do it this way:

By closedMenu = By.xpath(".//ul[not(contains(@class, 'is-open'))]");
By openMenu = By.xpath(".//ul[contains(@class, 'is-open')]");
By addItem = By.linkText("Add");
By addItemLocator = new ByChained(openMenu, addItem);

Upvotes: 0

demouser123
demouser123

Reputation: 4264

Try this //a[contains(text(),'Add')]

It may be used as driver.find_element_by_xpath("//a[contains(text(),'Add')]")

Upvotes: 0

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