Reputation: 15
I'm trying to insert images from a folder into a gallery made in javascript.
I'm using a php cycle to insert all the images but it doesn't work. Here is the code:
<div id="mygallery">
<?php $directory="img/portfolio";
$images=glob($directory . "*.jpg");
$swipebox = "swipebox";
foreach($images as $image) {
echo "<a href=" .$image." class=".$swipebox."> <img alt=" . $directory . "src=". $image . "/>";
}?></div>
Upvotes: 1
Views: 3146
Reputation: 1856
Above comments have mentioned two things. 1. Add slash (/) in path 2. Add Space between src and alt.
The list retuned by glob function is filenames/directory names matching given pattern. you have to join path in image source. Try below code. It should work.
<div id="mygallery">
<?php
$directory="img/portfolio/";
$images=glob($directory . "*.jpg");
$swipebox = "swipebox";
foreach($images as $image) {
echo "<a href=" .$image." class=".$swipebox."> <img alt=" . $directory . " src=". $directory .$image . " /></a>";
}
?>
</div>
Upvotes: 0
Reputation: 244
Here is the correct code:
<div id="mygallery">
<?php
$directory="img/portfolio/";
$images=glob($directory . "*.jpg");
$swipebox = "swipebox";
foreach($images as $image) {
echo "<a href=" .$image." class=".$swipebox."> <img alt=" . $directory . " src=". $image . " /></a>";
}
?>
</div>
Here are the mistake that you have done in your code:
1. Need to put slash '/' at after line no 3 after the image directory path
2. Need to put space between src
and alt
attribute at line no 7
Upvotes: 1
Reputation: 2449
Try below,
<?php
$allImageFiles = scandir('img/portfolio');
$swipebox = "swipebox";
foreach($allImageFiles as $key=>$image) {
echo "<a href=" .$image." class=".$swipebox."> <img alt=" . $directory . "src=". $image . "/>";
}
?>
Upvotes: 0
Reputation: 187
This is working, you needed a space before "src" and close the href.
<?php
$directory="img/portfolio";
$images=glob($directory . "*.jpg");
$swipebox = "swipebox";
foreach($images as $image) {
echo " <a href=" .$image." class=".$swipebox."> <img alt=" . $directory . " src='". $image . "' /> </a>";
}?>
Upvotes: 0