Reputation: 35
Good afternoon,
I am trying to send some values from a text form (made by Gravity Form) to a PHP file where I can then send those values to an API (Insightly). The reason for this is Insightly does not take AJAX calls.
The code I have is below, when I click the submit button I keep getting the "Failed To Send" error defined below, it never succeeds. So far I haven't finished my PHP scripting, I only have the following line:
$obj = $_POST['myData'];
I've been researching this issue for awhile now and still can't figure it out. Any assistance is greatly appreciated! Without further ado, here is the Javascript I have so far:
$(document).ready(function() {
$("#gform_submit_button_1").click(function() {
var name = document.getElementById("input_1_19").value;
// split name into first and last names
var fname = name.split(" ")[0];
var lname = name.split(" ")[1];
var company = document.getElementById("input_1_15").value;
var email = document.getElementById("input_1_6").value;
var phone = document.getElementById("input_1_14").value;
var hearAbout = document.getElementById("input_1_10").value;
var solution = document.getElementById("input_1_11").value;
var market = document.getElementById("input_1_17").value;
var details = document.getElementById("input_1_5").value;
var information =
{
"fname": fname,
"lname": lname,
"company":company,
"email": email,
"phone": phone,
"hearAbout": hearAbout,
"solution": solution,
"market": market,
"details": details
};
var dataString = JSON.stringify(information);
$.ajax({
type: "POST",
dataType: "json",
url: "insightlyAPI.php",
data: {myData: dataString},
success: function(data){
alert('AJAX Success!');
},
error: function(){
alert('Failed To Send');
}
});
});
});
Upvotes: 1
Views: 196
Reputation: 16172
The dataType
parameter you pass to $.ajax
call tell jQuery to expect data from the server:
"json": Evaluates the response as JSON and returns a JavaScript object. Cross-domain "json" requests are converted to "jsonp" unless the request includes jsonp: false in its request options. The JSON data is parsed in a strict manner; any malformed JSON is rejected and a parse error is thrown.
Try to return json from your PHP script, for example, add at the end:
echo json_encode(array());
Upvotes: 3