Reputation: 1951
i get a response from web api in the following format
{
"userId": "7c29a313-40ab-4927-bc43-7fc8518fe247",
"userName": "[email protected]",
"email": "[email protected]",
"mobileNumber": null,
"redirectTo": "none"
}
I try to parse it with following code
tvUserName.setText(new JSONObject(response).get("userName").toString());
but i get the following error
Value {"userId":"7c29a313-40ab-4927-bc43-7fc8518fe247","userName":"[email protected]","email":"[email protected]","mobileNumber":null,"redirectTo":"none"} of type java.lang.String cannot be converted to JSONObject
i can't find any mistake in the json file format, but still why do i get this error?
the async task is as follows
class authenticateLogin extends AsyncTask<Void, Void, String> {
private ProgressBar progressBar;
private Exception exception;
protected void onPreExecute() {
progressBar = (ProgressBar) findViewById(R.id.progressBar);
progressBar.setVisibility(View.VISIBLE);
//responseView.setText("");
}
protected String doInBackground(Void... urls) {
String result = "Error has occured";
try {
URL url;
URLConnection urlConn;
url = new URL(API_URL);
urlConn = url.openConnection();
urlConn.setDoInput(true);
urlConn.setDoOutput(true);
urlConn.setUseCaches(false);
urlConn.setRequestProperty("Content-Type", "application/json");
urlConn.setRequestProperty("Host", "api_app.azurewebsites.net");
urlConn.connect();
JSONObject jsonParam = new JSONObject();
jsonParam.put("loginid", "login");
jsonParam.put("password", "pass");
PrintWriter out = new PrintWriter(urlConn.getOutputStream());
out.print(jsonParam);
out.close();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConn.getInputStream()));
StringBuilder stringBuilder = new StringBuilder();
String line;
while ((line = bufferedReader.readLine()) != null) {
stringBuilder.append(line).append("\n");
}
bufferedReader.close();
result = stringBuilder.toString();
}
catch (java.io.IOException ex)
{
result = "IO-Error: " + ex.getMessage();
Log.e("IO Error Tag",ex.getStackTrace().toString());
}
catch (org.json.JSONException ex)
{
result = "JSON-Error: " + ex.getMessage();
}
return result;
}
protected void onPostExecute(String response) {
if(response == null) {
response = "THERE WAS AN ERROR";
}
progressBar.setVisibility(View.GONE);
Log.i("INFO", response);
//responseView.setText(response);
}
}
Upvotes: 0
Views: 2199
Reputation: 8067
Create JsonParser.java And just copy-paste this code
JsonParser.java
package info.tranetech.laundry.adapter;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.utils.URLEncodedUtils;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import java.io.IOException;
import java.io.UnsupportedEncodingException;
import java.util.List;
public class JSONParser {
static String response = null;
public final static int GET = 1;
public final static int POST = 2;
public JSONParser() {
}
/**
* Making service call
* @url - url to make request
* @method - http request method
* */
public String makeServiceCall(String url, int method) {
return this.makeServiceCall(url, method, null);
}
/**
* Making service call
* @url - url to make request
* @method - http request method
* @params - http request params
* */
public String makeServiceCall(String url, int method,
List<NameValuePair> params) {
try {
// http client
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpEntity httpEntity = null;
HttpResponse httpResponse = null;
// Checking http request method type
if (method == POST) {
HttpPost httpPost = new HttpPost(url);
// adding post params
if (params != null) {
httpPost.setEntity(new UrlEncodedFormEntity(params));
}
httpResponse = httpClient.execute(httpPost);
} else if (method == GET) {
// appending params to url
if (params != null) {
String paramString = URLEncodedUtils
.format(params, "utf-8");
url += "?" + paramString;
}
HttpGet httpGet = new HttpGet(url);
httpResponse = httpClient.execute(httpGet);
}
httpEntity = httpResponse.getEntity();
response = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return response;
}
}
And call in doInBackground like this
@Override
protected Void doInBackground(Void... arg0) {
// Creating service handler class instance
JSONParser JP = new JSONParser();
// Making a request to url and getting response
String jsonStr = JP.makeServiceCall("http://.com/mis/Laundry/men_dry.php", JSONParser.GET);
Log.d("Response: ", "> " + jsonStr);
if (jsonStr != null) {
try {
JSONObject jsonObj = new JSONObject(jsonStr);
String A = jsonObj.getString("userId").toString();
}
} catch (JSONException e) {
e.printStackTrace();
}
} else {
Log.e("ServiceHandler", "Couldn't get any data from the url");
}
return null;
}
Upvotes: 0
Reputation: 48307
You should use instead:
tvUserName.setText(new JSONObject(response).getString("userName"));
Upvotes: 1