CODEWITHSUNDEEP
python
geshtin
geshtin

Reputation: 3

Determining whether a list consist of unique elements

I found some solutions in this forum, but they do not work quite the way I hoped. The following input data is used:

ALY1 ATH BOL BRA
ALY2 ATH BOL BRA
ALY3 ATH BOL BRA
ALY4 ATH BOL BRA
ALY5 BOL BOL BRA
ALY6 ATH BOL BRA BOL

I want to keep only lines 1,2,3, and 4. But not 5 and 6, as here duplicates occur. The following is what I used:

f_groups = open(args[1], "r")
f_idl_group = open(args[2], "w")
def allUnique(x):
    seen = set()
    return not any(i in seen or seen.add(i) for i in x)

for line in f_groups :
    line_elements = line.split()
    identifyers = line_elements[0:]
    if allUnique(identifyers) :
        print("all is well" + identifyers[0])
        #write to file

Using the script as above, all lines pass, but using :

if not allUnique(identifyers) :

Then only lines 5 and 6 pass. The latter is what I would expect, but I want the opposite, only to pass lines 1, 2, 3, and 4. Which fails. Any help is appreciated. Thanks.

Upvotes: 0

Views: 59

Answers (1)

Tom Karzes
Tom Karzes

Reputation: 24052

Try this:

def allUnique(x):
    return len(x) == len(set(x))

This will return True if all elements in list x are unique, otherwise False. set(x) is a set of the elements of x, with any duplicates removed. If it has the same element count as x, then there were no duplicates. Otherwise there were.

Upvotes: 4

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