CODEWITHSUNDEEP
javascriptarraysregexstringfilter
Daniel
Daniel

Reputation: 6491

Remove empty or whitespace strings from array - Javascript

I've found this beautiful method for removing empty strings - arr = arr.filter(Boolean).

But it doesn't seem to work on whitespace strings.

var arr = ['Apple', '  ', 'Mango', '', 'Banana', ' ', 'Strawberry'];
arr = arr.filter(Boolean);
// ["Apple", "  ", "Mango", "Banana", " ", "Strawberry"]

// should be ["Apple", "Mango", "Banana", "Strawberry"]

Is there a nice way to expand this method to removing whitespaces as well or should i trim the whitespaces by iterating the array first?

Upvotes: 29

Views: 65489

Answers (9)

VU TIEN LUONG
VU TIEN LUONG

Reputation: 1

function clearSpace(arr){
    for (var key in arr) {
        if (arr[key] == "") {
            arr.splice(key, 1)
            clearSpace(arr)
        }
    }
}
var arr = ["","a","b","",""]
clearSpace(arr)
console.log(arr)

//I hope this helps you!!
//Vu Tien Luong - 3GTEL

Upvotes: 0

Vic_Gayday
Vic_Gayday

Reputation: 11

I used filter and checking if element length is not equal to zero. It worked for me, and this solution is short:

const arr = ['Apple', '', 'Mango', '', 'Banana', '', 'Strawberry']

const arr2 = arr.filter(item => item.length !== 0)          

console.log(arr2)

Upvotes: 0

shreyasm-dev
shreyasm-dev

Reputation: 2834

A one-line solution written in ES6 for quick use:

const filterArray=a=>a.filter(x=>typeof x!=='string'||!!x.trim())

Some advantages of this are that it ignores anything that is not a string.

Without ES6:

function filterArray(a) {
  return a.filter(function(x) {
    return typeof x !== 'string' || !!x.trim()
  })
}

Example:

const filterArray=a=>a.filter(x=>typeof x!=='string'||!!x.trim())

console.log(filterArray([1, 2, 4, '', '']))

Or if your browser doesn't support ES6 (which it probably does):

function filterArray(a) {
  return a.filter(function(x) {
    return typeof x !== 'string' || !!x.trim()
  })
}

console.log(filterArray([1, 2, 4, '', '']))

Upvotes: 0

Kodiswaran K
Kodiswaran K

Reputation: 11

const fruits = ['Apple', undefined, ' ', 'Mango', '', 'Banana', ' ', 'Strawberry'];

fruits.filter(fruit => fruit && fruit.trim())

Output: ["Apple", "Mango", "Banana", "Strawberry"]

Filter condition: fruit && fruit.trim()

prefix - will remove all the falsy value
suffix - will trim and then remove all the falsy values

Upvotes: 0

T.J. Crowder
T.J. Crowder

Reputation: 1075219

filter works, but you need the right predicate function, which Boolean isn't (for this purpose):

// Example 1 - Using String#trim (added in ES2015, needs polyfilling in outdated
// environments like IE)
arr = arr.filter(function(entry) { return entry.trim() != ''; });

or

// Example 2 - Using a regular expression instead of String#trim
arr = arr.filter(function(entry) { return /\S/.test(entry); });

(\S means "a non-whitespace character," so /\S/.test(...) checks if a string contains at least one non-whitespace char.)

or (perhaps a bit overboard and harder to read)

// Example 3
var rex = /\S/;
arr = arr.filter(rex.test.bind(rex));

With an ES2015 (aka ES6) arrow function, that's even more concise:

// Example 4
arr = arr.filter(entry => entry.trim() != '');

or

// Example 5
arr = arr.filter(entry => /\S/.test(entry));

Live Examples -- The ES5 and earlier ones:

var arr = ['Apple', '  ', 'Mango', '', 'Banana', ' ', 'Strawberry'];
console.log("Example 1: " + JSON.stringify(arr.filter(function(entry) { return entry.trim() != ''; })));
console.log("Example 2: " + JSON.stringify(arr.filter(function(entry) { return /\S/.test(entry); })));
var rex = /\S/;
console.log("Example 3: " + JSON.stringify(arr.filter(rex.test.bind(rex))));

...and the ES2015 (ES6) ones (won't work if your browser doesn't support arrow functions yet):

var arr = ['Apple', '  ', 'Mango', '', 'Banana', ' ', 'Strawberry'];
console.log("Example 4: " + JSON.stringify(arr.filter(entry => !entry.trim() == '')));
console.log("Example 5: " + JSON.stringify(arr.filter(entry => /\S/.test(entry))));

Upvotes: 67

Atit More
Atit More

Reputation: 155

You Can try this approach. I found this process simple and it work for me.

let arrayEle = ["abc", " "," ", "def", "xyz", " "]; 

  arrayEle = arrayEle.filter((element) => {
    return /\S/.test(element);
  });
  
  console.log(arrayEle);
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.7.5/angular.min.js"></script>

Upvotes: 0

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627291

Based on this MDN reference:

\s
Matches a single white space character, including space, tab, form feed, line feed and other Unicode spaces. Equivalent to [ \f\n\r\t\v​\u00a0\u1680​\u180e\u2000​-\u200a​\u2028\u2029\u202f\u205f​\u3000\ufeff].

And on ECMA 262 reference, saying \s should match "White Space" like \u0009 (Tab, <TAB>), \u000B (Vertical Tab, <VT>), \u000C (Form Feed, <FF>), \u0020 (Space, <SP>), \u00A0 (No-break space, <NBSP>), \uFEFF (Byte Order Mark, <BOM>), and other category “Zs” (<USP>), and also "line terminators" like \u000A (Line Feed, <LF>), \u000D (Carriage Return, <CR>), \u2028 (Line separator, <LS>) and \u2029 (Paragraph separator, <PS>), you can use the following code to remove elements that are either empty or whitespace only if trim() is not natively available:

var arr = ['Apple', '  ', 'Mango', '', 'Banana', ' ', 'Strawberry'];
arr = arr.filter(s => s.replace(/\s+/g, '').length !== 0);
// Or for ES5
// arr = arr.filter(function (el) { return el.replace(/\s+/g, '').length !== 0; });
console.log(arr);

In case some old browsers behave differently with \s, replace it with [ \f\n\r\t\v​\u00a0\u1680​\u180e\u2000​-\u200a​\u2028\u2029\u202f\u205f​\u3000\ufeff] character class:

arr = arr.filter(function (el) { return el.replace(/[ \f\n\r\t\v​\u00a0\u1680​\u180e\u2000​-\u200a​\u2028\u2029\u202f\u205f​\u3000\ufeff]+/g, '').length !== 0; });

And you can also customize it further to include new Unicode spaces to come.

Upvotes: 5

guest271314
guest271314

Reputation: 1

Could use Array.protype.join(), String.prototype.split() with parameter RegExp /\s|,/ followed by .filter(Boolean)

var arr = ['Apple', '  ', 'Mango', '', 'Banana', ' ', 'Strawberry'];
arr = arr.join().split(/\s|,/).filter(Boolean);
console.log(arr)

Upvotes: -1

Tushar
Tushar

Reputation: 87233

You can take advantage of empty string as falsy value.

You can use Array#filter with String#trim.

Using ES6 Arrow function:

arr = arr.filter(e => String(e).trim());


var arr = ['Apple', '  ', 'Mango', '', 'Banana', ' ', 'Strawberry'];
var nonEmpty = arr.filter(e => String(e).trim());

document.getElementById('result').innerHTML = JSON.stringify(nonEmpty, 0, 4);
<pre id="result"></pre>

Using ES5 anonymous function:

arr = arr.filter(function(e) {
    return String(e).trim();
});


var arr = ['Apple', '  ', 'Mango', '', 'Banana', ' ', 'Strawberry'];
var nonEmpty = arr.filter(function(e) {
    return String(e).trim();
});

document.getElementById('result').innerHTML = JSON.stringify(nonEmpty, 0, 4);
<pre id="result"></pre>

Upvotes: 22

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