CODEWITHSUNDEEP
python
user47467
user47467

Reputation: 1093

Python remove one worded strings from list

words = [['hey', 'hey you'], ['ok', 'ok no', 'boy', 'hey ma']]

I have a list of lists containing strings. I understand how to remove specific elements from a list, but not how to remove those that are only one word. My desired output would be:

final = [['hey you'], ['ok no', 'hey ma']]

What I'm trying but I think it's totally wrong....

remove = [' ']
check_list = []

for i in words:
    tmp = []
    for v in i:
        a = v.split()
        j = ' '.join([i for i in a if i not in remove])
        tmp.append(j)

    check_list.append(tmp)
print check_list

Upvotes: 3

Views: 121

Answers (4)

AndreyT
AndreyT

Reputation: 1499

You can use filter:

for words in list_of_lists: 
    words[:] = list(filter(lambda x: ' ' in x.strip(), words))

Or list comprehension:

for words in list_of_lists:
    words[:] = [x for x in words if ' ' in x.strip()]

Upvotes: 2

Suresh Mali
Suresh Mali

Reputation: 348

Here is the logic for each list, this you can loop and use

wordlist=['hey', 'hey you']
filter(None,  [ p if re.sub('\\b\\w+\\b', '', p) != '' else None for p in wordlist ])

output

['hey you']

Upvotes: -1

Tony Babarino
Tony Babarino

Reputation: 3405

Functional programming way to do that:

>>> words
[['hey', 'hey you'], ['ok', 'ok no', 'boy', 'hey ma']]
>>> map(lambda v: ' '.join(v),
    filter(lambda y: len(y) > 1, map(lambda x: x.split(), words[1])))
['ok no', 'hey ma']
>>> map(lambda z: map(lambda v: ' '.join(v),
    filter(lambda y: len(y) > 1, map(lambda x: x.split(), z))), words)
[['hey you'], ['ok no', 'hey ma']]

Upvotes: 0

Julien Spronck
Julien Spronck

Reputation: 15423

You can do:

words = [['hey', 'hey you'], ['ok', 'ok no', 'boy', 'hey ma']]
final = [[x for x in sub if ' ' in x.strip()] for sub in words]
# [['hey you'], ['ok no', 'hey ma']]

where I simply search for spaces in all strings.

Upvotes: 5

Related Questions