CODEWITHSUNDEEP
pythonpython-2.7dictionary
gwthm.in
gwthm.in

Reputation: 638

Python Dictionaries | ZIP | dict(zip())

I have a problem with python zip and dictionaries. I have list called dirs which contains all directory names. I want to generate something like the below one

dirs_count = {'placements':{'total':0,'Others':0},'x-force':{'total':0,'Others':0})

I used the following code to generate this.

dirs = ['placemetns', 'x-code']
dirs_count = dict(zip(dirs,[{'total':0, 'others': 0}]*len(dirs)))
# {'placements':{'total':0,'others':0},'x-code':{'total':0,'others':0}}

But the problem here is, if I modify one dictionary value, the following thing happens..

dirs_count['placements']['total'] = 5
# {'placements':{'total':5,'others':0},'x-code':{'total':5,'others':0}}

Is there any way to prevent this?
or
Is there any way to generate dirs_count in which it doesn't effect the entier dictionary on modification?

Upvotes: 0

Views: 1916

Answers (2)

leongold
leongold

Reputation: 1044

Use dirs_count = {d: {'total': 0, 'others': 0} for d in dirs}.

What happens in your case is that both placements and x-code refer to the same object.

Upvotes: 3

nathan.medz
nathan.medz

Reputation: 1603

This is happening because [{'total':0, 'others': 0}]*len(dirs) gives you a number of references to the same dict, so any changes to one will affect all the copies. try instead 

dirs = ['placemetns', 'x-code']
dicts = [{'total':0, 'others': 0} for i in dirs]
dirs_count = dict(zip(dirs,dicts))

Upvotes: 1

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